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Vilka [71]
2 years ago
11

Applying descriptive statistics and data visualization to the training set to understand the data and assist in the selection of

an appropriate technique is a part of ________.
a. model assessment.
b. data partitioning.
c. data preparation.
d. data exploration.
Mathematics
1 answer:
lianna [129]2 years ago
4 0

Answer:

i think it might be A

Step-by-step explanation:

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Shaniqua has $45 in her wallet. She spends $4 on snacks and $8 on a movie ticket. What integer represents the change in the amou
Ivenika [448]

Answer:33 left :)

Step-by-step explanation:

8 0
2 years ago
The Cool Company determines that the supply function for its basic air conditioning unit is S(p) = 40 + 0.008p3 and that its dem
myrzilka [38]

We are given the functions:

<span>S (p) = 40 + 0.008 p^3                                     ---> 1</span>

<span>D (p) = 200 – 0.16 p^2                                     ---> 2</span>

 

T o find for the price in which the price of supply equals demand, all we have to do is to equate the two equations, equation 1 and 2, and calculate for the value of p, therefore:

S (p) = D (p)

40 + 0.008 p^3 = 200 – 0.16 p^2

0.008 p^3 + 0.16 p^2 = 160

p^3 + 20 p^2 = 20,000

p^3 + 20 p^2 – 20,000 = 0

Calculating for the roots using the calculator gives us:

p = 21.86, -20.93±21.84i

 

Since price cannot be imaginary therefore:

p = 21.86

3 0
2 years ago
Masha is making a scale diagram of the front face of an aquarium. The face is shaped like a rectangle. She uses a scale of 1 cen
dangina [55]
14 feet because 5+5+2+2 equals 14
4 0
2 years ago
A family recycled 66 cans in February, 94 cans in March, 122 cans in April, and 150 cans in May. If this pattern went from Janua
fredd [130]

Step-by-step explanation:

Difference per month = 28

=> January = February - 28 = 66-28 = 38

3 0
2 years ago
CL 6-131. Solve each system using the method of your choice.
shepuryov [24]

System 1: The solution is (x, y) = (-4, 5)

System 2:  The solution is (x, y) = (\frac{11}{3}, -3)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 7 ------ eqn 1

-3x - 5y = -13 --------- eqn 2

We can solve by elimination method

Multiply eqn 1 by 3

6x + 9y = 21 ------ eqn 3

Multiply eqn 2 by 2

-6x - 10y = -26 ------- eqn 4

Add eqn 3 and eqn 4

6x + 9y -6x - 10y = 21 - 26

-y = -5

y = 5

Substitute y = 5 in eqn 1

2x + 3(5) = 7

2x + 15 = 7

2x = -8

x = -4

Thus the solution is (x, y) = (-4, 5)

<h3><em><u>Second system of equation is:</u></em></h3>

8 - y = 3x ------ eqn 1

2y + 3x = 5 ----- eqn 2

We can solve by susbtitution method

From given,

y = 8 - 3x ----- eqn 3

Substitute eqn 3 in eqn 2

2(8 - 3x) + 3x = 5

16 - 6x + 3x = 5

3x = 16 - 5

3x = 11

x = \frac{11}{3}

Substitute the above value of x in eqn 3

y = 8 - 3x

y = 8 - 3 \times \frac{11}{3}\\\\y = 8 - 11\\\\y = -3

Thus the solution is (x, y) = (\frac{11}{3}, -3)

4 0
2 years ago
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