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2 years ago

Rob found 103 + 1875 = x using mental math. Use at least 3 terms from the world list to describe how Rob could find the sum.

Mathematics

1 answer:

arlik [135]2 years ago

6 0

Answer:

Make, sum, total

Step-by-step explanation:

There are many terms in the word list that could be used to describe how Rob had solved the sum in his head. He had made and arranged numbers vertically in his head then sum it and at last he found the total.

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A chain weighs 10 pounds per foot. How many ounces will 4 inches weigh?

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4in*(ft/12in)*(10lb/ft)*(16oz/lb)=53 1/3 oz

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2 years ago

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Shawna and her best friend Keisha go shopping. The function p(x) = 3x4 + 2x3 − 4x2 + 21 represents how much money each girl spen

tino4ka555 [31]

Answer:

$69

Step-by-step explanation:

Given the amount of money each girl spent based on the number of hours they were shopping modeled by the function p(x) = 3x4 + 2x3 − 4x2 + 21

To get how much they spend together if each go shopping for 2hours, we will substitute x = 2 into the given function as shown:

p(2) = 3(2)⁴ + 2(2)³ − 4(2)² + 21

p(2) = 3(16) + 2(8) − 4(4) + 21

p(2) = 48 + 16 − 16 + 21

p(2) = 48+21

p(2) = 69

Therefore they spend $69 together

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2 years ago

Giuseppe is studying shark attacks around the world and finds that most such attacks occur during the day. He concludes that sha

HACTEHA [7]

Answer:

C) not justified, since people usually swim in the ocean during the day.

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2 years ago

A group of 18 people ordered soup and sandwiches for lunch. Each person in the group had either one soup or one sandwich. The sa

sergeinik [125]

X - the number of sandwiches ordered
y - the number of soups ordered

There were 18 people, and each person ordered either one soup or one sandwich.
$x+y=18$

The sandwiches cost $7.75 each, the soups cost $4.50 each. The total cost was $113.50.
$7.75x+4.5y=113.5$

Set up a system of equations:
$x+y=18 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times (-4.5) \\
7.75x+4.5y=113.5 \\ \\
-4.5x-4.5y=-81 \\
\underline{7.75x+4.5y=113.5} \\
3.25x=32.5 \\
x=\frac{32.5}{3.25} \\
x=10$

10 sandwiches were ordered.
The answer is D.

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2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

The probability, $P =0.0002$

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago