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masya89 [10]
2 years ago
8

Find the measure of b. A. 80 B. 70 C. 40 D. 20

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
8 0

Answer:

40°

Step-by-step explanation:

e = 20°

d = 20°

c = 140°

b = 40°

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i think you add both fabric prices then divide with 5.50

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The first three terms of a geometric sequence are shown below. x+3,-2x2-6x,4x3+12x2,.... What is the eighth term of the sequence
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So hmm is a geometric sequence, meaning, the next term is found by multiplying it by "something", namely the "common ratio"

now, if the next term is the product of the common ratio and the previous term, that means, if we divide the previous term by the next term, the quotient will then be the "common ratio", let's do that then

let's divide the 2nd term by the 1st term then

\bf \cfrac{-2x^2-6x}{x+3}\implies \cfrac{-2x\underline{(x+3)}}{\underline{(x+3)}}\implies \boxed{-2x}\impliedby \textit{common ratio}\\\\
-----------------------------\\\\

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{value of first term}\\
r=\textit{common ratio}\\
----------\\
a_1=x+3\\
n=8\\
r=-2x
\end{cases}
\\\\\\
a_8=(x+3)(-2x)^{8-1}\implies a_8=(x+3)(-2x)^7
\\\\\\
a_8=(x+3)(-2^7x^7)\implies a_8=(x+3)(-128x^7)
\\\\\\
a_8=-128x^8-384x^7
8 0
2 years ago
Read 2 more answers
Mia’s work to find the slope of a trend line through the points (3, 10) and (35, 91) is shown below.
pochemuha
For this case the first thing you should know is that by definition the slope of the line is given by:
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Investigate the following harvesting model both qualitatively and analytically. If a constant number h of fish are harvested fro
zalisa [80]

Answer:

a. The population does not become extinct in finite time.

Step-by-step explanation:

The model for the population of the fishery is

dP/dt = P(a-bP)-h, P(0) = P_0

If we rearrange and replace the constants we have:

\frac{dP}{P(7-P)-49/4} =dt\\\\-4 (\frac{dP}{4(P-7)P+49}) =dt\\\\-4 \frac{dP}{(2P-7)^2} =dt\\\\-4 \int\frac{dP}{(2P-7)^2} =\int dt\\\\-4(-\frac{1}{2(2P-7)})=t+C\\\\\frac{2}{2P-7}=t+C\\\\ t=0 \,\,\, P(0)=P_0\\\\\frac{2}{2P_0-7}=0+C\\\\C=\frac{2}{2P_0-7}

Now we can calculate if the population become 0 in any finite time

\frac{2}{2P-7}=t+\frac{2}{2P_0-7}\\\\\frac{2}{2*0-7}=t+\frac{2}{2P_0-7}\\\\-\frac{2}{7}=t+\frac{2}{2P_0-7}\\\\

To be a finite time, t>0

t=-\frac{2}{7}-\frac{2}{2P_0-7}=0\\\\-\frac{2}{2P_0-7}=\frac{2}{7}\\\\7-2P_0=7\\\\P_0=0

We can conclude that the only finite time in which P=0 is when the initial population is 0.

Because P0 is a positive constant, we can say that the population does not become extint in finite time.

5 0
2 years ago
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