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Murrr4er [49]
2 years ago
11

In what line do planes A and QRV intersect?

Mathematics
1 answer:
BabaBlast [244]2 years ago
6 0

Answer:

Plane A and QRV intersection line is QR.

Explanation:

The plane QRV contains the rectangle QRVN. This rectangle intersects the plane A in the line QR.

Plane A and QRV intersection line is QR.

If one knows a specific line in one plane (for example, two points in the plane), and this line intersects the other plane, then its point of intersection.

Thus, it is on the line of intersection for the two planes.


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On a coordinate plane, an exponential function has a horizontal asymptote of y = 0. The function goes through points (negative 2
stepan [7]

Answer:

3

Step-by-step explanation:

i had it

4 0
2 years ago
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Use the coordinates of the labeled point to find the point-slope equation of the line
koban [17]

Answer:

A. y + 1 = -2(x-2)

Step-by-step explanation:

point-slope equation is : y - y1 = m (x -x1)

remember m= slope value

the given point is (2, -1) therefore we can substitute the values in:

y + 1 = m(x -2)

now to make sure our answer is complete we will solve for the slope:

looking back at the graph, the y-intercept value is 3, therefore we have a point of (0,3) and (2, -1)

with any two points you can determine a slope.

y2 - y1 / x2 - x1

therefore :

-1 -3 / 2 - 0

-4 / 2 = -2

therefore our m value is -2

this makes the completed point-slope equation:

y + 1 = -2 (x - 2) or A

3 0
1 year ago
Mia is rolling a pair of 6-sided dice.
tekilochka [14]

Answer:

The domain of P is given by,

{n | n ∈ N, 2 ≤ n ≤ 12}

Step-by-step explanation:

A perfect die is perfectly cubic in shape with one of the integers 1,2,3,4, 5 or 6 in each of it's 6 faces and the digits on any two faces are different.

Now, two dice are rolled and P(n) models the probability of the event that the sum on the faces of the two dice is n.

Hence, the domain of P is given by,

{n | n ∈ N, 2 ≤ n ≤ 12}

7 0
1 year ago
Read 2 more answers
Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
mars1129 [50]

Answer: In the beginning he was given 27 sweets.

Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.

On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;

8/a = 2/3

By cross multiplication we now have

8 x 3 = 2a

24/2 = a

a = 12

Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;

12/b = 2/3

By cross multiplication we now have

12 x 3 = 2b

36 = 2b

36/2 = b

b = 18

Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;

18/x = 2/3

By cross multiplication we now have

18 x 3 = 2x

54 = 2x

x = 27

Therefore Tim was given 27 sweets at the beginning.

3 0
2 years ago
Subtract 7x + 4y − 2z from 4x + 2y.
sukhopar [10]

Answer:

-3x-6y-2z

Step-by-step explanation:

(4x - 2y)-(7x+4y-2z) = 4x-2y-7x-4y-2z = -3x-6y-2z

I hope that's the answer.

7 0
1 year ago
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