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Murrr4er [49]
1 year ago
11

In what line do planes A and QRV intersect?

Mathematics
1 answer:
BabaBlast [244]1 year ago
6 0

Answer:

Plane A and QRV intersection line is QR.

Explanation:

The plane QRV contains the rectangle QRVN. This rectangle intersects the plane A in the line QR.

Plane A and QRV intersection line is QR.

If one knows a specific line in one plane (for example, two points in the plane), and this line intersects the other plane, then its point of intersection.

Thus, it is on the line of intersection for the two planes.


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miss Akunina [59]

Answer:

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Step-by-step explanation:

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1 year ago
Compare the mathematical meaning of the word limit with its commonly used meanings. For the word’s mathematical meaning, think o
vredina [299]
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1 year ago
Mrs.Steffen’s third grade class has 30 students in it. The students are divided into three groups(numbered 1, 2,and 3),each havin
qaws [65]

Answer:

a. \\ 10! = 3628800;

b. \\ 10!*10!*10! = 47784725839872000000 = 4.7784725839872*10^{19}

Step-by-step explanation:

We need here to apply the <em>Multiplication Principle </em>or the <em>Fundamental Principle of Counting</em> for each answer. Answer <em>b</em> needs an extra reasoning for being completed.

The <em>Multiplication Principle</em> states that if there are <em>n</em> ways of doing something and <em>m</em> ways of doing another thing, then there are <em>n</em> x <em>m</em> ways of doing both (<em>Rule of product</em> (2020), in Wikipedia).

<h3>In how many ways can ten students line up? </h3>

There are <em>ten</em> students. When one is selected, there is no other way to select it again. So, <em>no repetition</em> is allowed.

Then, in the beginning, there are 10 possibilities for 10 students; when one is selected, there are nine possibilities left. When another is selected, eight possibilities are left to form the file, and so on.

Thus, we need to multiply the possibilities after each selection: that is <em>why</em> the <em>Multiplication Principle</em> is important here.

This could be expressed mathematically using n!:

\\ n! = n * (n-1)! * (n-2)! *...* 2*1.

For instance, \\ 5! = 5 * (5-1)! * (5-2)! *...*2*1 = 5 * 4 * 3 * 2 * 1 = 120.

So, for the case in question, the <em>ten</em> students can line up in:

\\ 10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3628800 ways to line up in a single file.

<h3>Second Question</h3>

For this question, we need to consider the former reasoning with extra consideration in mind.

The members of Group 1 can occupy <em>only</em> the following places in forming the file:

\\ G1 = \{ 1, 4, 7, 10, 13, 16, 19, 22, 25, 28\}^{th} <em>places</em>.

The members of Group 2 <em>only</em>:

\\ G2 = \{ 2, 5, 8, 11, 14, 17, 20, 23, 26, 29\}^{th} <em>places</em>.

And the members of Group 3, the following <em>only</em> ones:

\\ G3 = \{ 3, 6, 9, 12, 15, 18, 21, 24, 27, 30\}^{th} <em>places.</em>

Well, having into account these possible places for each member of G1, G2 and G3, there are: <em>10! ways</em> for lining up members of G1; <em>10! ways</em> for lining up members of G2 and, also, <em>10! ways</em> for lining up members of G3.

After using the <em>Multiplication Principle</em>, we have, thus:

\\ 10! * 10! * 10! = 47784725839872000000 = 4.7784725839872 *10^{19} <em>ways the students can line up to come in from recess</em>.

3 0
1 year ago
At a local fitness center, members pay a $14 membership fee and $5 for each aerobics class. Nonmembers pay $6 for each aerobics
nata0808 [166]

Answer:

that would be $25 for each.

5 0
1 year ago
Read 2 more answers
A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th
Kitty [74]

Answer:

a

   The  90%  confidence interval is  52561.13  <  \mu  < 57540.8

b

Confidence interval for the population men between <u>$52561.13</u>  up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 25

     The  sample mean is  \= x  =  \$ 55,051

     The standard deviation is  \sigma  =  \$ 7,568

Given that the confidence level is  90% then the level of confidence is mathematically represented as

             \alpha  =  100 -90

              \alpha  = 10\%

             \alpha  = 0.10

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table the values is  

               Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically  represented as

               E =  Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }

substituting values

               E =  1.645 * \frac{ 7568}{ \sqrt{ 25} }

             E =  2489.9

The 90% confidence interval is mathematically evaluated as

       \= x  -E  <  \mu  <  \= x  +E

substituting values

     55051  - 2489.8  <  \mu  <  55051  + 2489.8

     52561.13  <  \mu  < 57540.8

6 0
2 years ago
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