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Rom4ik [11]
2 years ago
6

The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. Conveyor belts can vary from the ideal width by a

t most 7/32in. Which of the following represents the acceptable widths for the conveyor belt? Check all that apply.
x>=49 25/32
x<=50 7/32
49 25/32<=x<=50 7/32
x+7/32<=50
|x-50|< 7/32

Mathematics
1 answer:
Gennadij [26K]2 years ago
7 0
<h3><u>Answer:</u></h3>

The answer is:

|x-50|\leq \dfrac{7}{32}

49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

<h3><u>Step-by-step explanation:</u></h3>

The ideal  width of a certain conveyor belt for a manufacturing plant is 50 in.

Conveyor belts can vary from the ideal width by at most 7/32 in.

i.e. the absolute change in the width has to be less than or equal to 7/32 in. and it can't exceed more than that.

That is if it will decrease than the  the acceptable width for the conveyor belt is represented by the expression;

|x-50|\leq \dfrac{7}{32}

Also on solving it we get:

\dfrac{-7}{32}\leq x-50\leq \dfrac{7}{32}\\\\\\50-\dfrac{7}{2}\leq x\leq 50+\dfrac{7}{2}\\\\49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

Hence, the correct choices are:

|x-50|\leq \dfrac{7}{32}

49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

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BlackZzzverrR [31]
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Next, we can parameterize the surface by

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so that the surface element is

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=20\sqrt{42}(1-v)\,\mathrm du\,\mathrm dv

Then the area of \mathcal S is given by the surface integral

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2 years ago
A simple random sample of 100 concert tickets was drawn from a normal population. The mean and standard deviation of the sample
alexandr402 [8]

Answer:

We accept the null hypothesis and the population mean is $120.

Step-by-step explanation:

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Sample standard deviation, s = $25

First, we design the null and the alternate hypothesis

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We use two-tailed t test to perform this hypothesis.

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Step-by-step explanation:

Dos números consecutivos se escriben como:

n y (n + 1)

done n es un numero entero.

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Se escribe como:

n*(n + 1) = 552

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Tenemos una cuadrática, las posibles soluciones son obtenidas con la formula de Bhaskara.

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