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likoan [24]
2 years ago
6

The graph of function g is a vertical stretch of the graph of function f ​​by a factor of 3. Which equation describes function g

?
​​ g(x)=f(x3)

g(x)=3f(x)

​​ g(x)=13f(x)

​​ g(x)=f(3x)

Mathematics
2 answers:
DIA [1.3K]2 years ago
7 0
<h3><em>g(x)=3f(x) describes function G</em></h3>

<em>i just took the test i can confirm this is the answer </em>


forsale [732]2 years ago
6 0

Answer: The correct option is second, i.e., g(x)=3f(x).

Explanation:

A functions g(x) is stretch or compressed of graph of function f(x) is defined by the equation,

g(x)=kf(x)

Where, k is a constant and it shows the compress or stretch factor.

If k>0, then it is a stretch factor and the graph of f(x) is stretched by factor of k.

If k<0, then it is a compress factor and graph of f(x) is compressed by factor k.

Since the graph of g(x) is a vertical stretch of the graph of function f(x) ​​by a factor of 3, therefore,

g(x)=3f(x)

So, the option second is correct.

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If week 1=5, week 2=3, week 3=7, week 4=5 what will week 5 be?
olga2289 [7]

Answer: 11

Step-by-step explanation:

The sequence goes +4, +1, +5, +1... so obviously the next number will be +6. So, 5+6=11

The answer is week 5=11

4 0
2 years ago
During the first seconds after takeoff, a rocket traveled 208 kilometers in 50 minutes at a constant rate suppose a penny is dro
andrezito [222]

the penny travels at a faster rate by 56.4 kilometers

penny = 153 for 30 min

penny = 306 for 1 hour

rocket = 208 in 50 min

208/5 = 41.6 *6 = 249.6 in 1 hour

penny is faster by 56.4 kilometers

6 0
2 years ago
jack wants to weigh at most 176 pounds before the baseball season begins. he has already lost 15 pounds. he belives he can lose
VikaD [51]
The answer will be 4 weeks. You know the constant is 1.5 lbs per week and you will multiply that by however many weeks it takes to reach 176
197-(1.5x) would be your equation and since he’s already lost 15 pounds you will include that by subtracting 15 from the equation as well 197-(1.5(4))=191
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6 0
2 years ago
Kara starts tying a baby quilt at the local community center. Each quilt takes 200 ties to complete. Ten minutes later Julie joi
Tju [1.3M]

Answer:

a) K(t)=6\frac{tie}{min}(t)

b)J(t)=11\frac{tie}{min}(t)

c)T_{f}(t)=K(t+10)+J(t) where T_{f}(t)= number ties finished per unit time

d) t≅8.24min

e) K=109tie

   J=91tie

f) K≅16.6min

  J≅9.09min

Step-by-step explanation:

Data

Kara_{(K)}=6\frac{tie}{min}\\Julie(J)=11\frac{tie}{min}

Kara begins ten minutes before julie, so when julie joins kara she has 60 ties

t=10 k=6\frac{tie}{min}*10min=60tie

a) K(t)=6\frac{tie}{min}(t)

b)J(t)=11\frac{tie}{min}(t)

c)T_{f}(t)=K(t+10)+J(t) where T_{f}(t)= number ties finished per unit time

d) if kara already has 60 ties and makes 6 per minute and Julie makes 11 per minute then per minute they makes 17 ties, so one minute per 17 ties for 200 ties ¿how long?. t=\frac{(200-60)tie*min}{17tie}≅8.24min

e) K=60tie+6tie/min*8.24min=109tie

   J=11tie/min*8.24min=91tie

f) K=100tie*min/6tie≅16.6min

  J=100tie*min/11tie≅9.09min

Note: the amount of ties were rounded to the nearest decimal

6 0
2 years ago
Find the truth set of each predicate. (If your answer is an interval, enter it using interval notation; otherwise enter it as a
makvit [3.9K]

(a) Predicate: 10d is an integer

The domain is \mathbb{Z}. In fact, integers are closed under multiplication, and 10 is an integer. So, if d is an integer, 10d is a multiplication between integers, and thus an integer.

(c) 1\leq x^2\leq 4

Since 1 and 4 are both squares, we have

1\leq x^2 \leq 4 \iff 1^2\leq x^2 \leq 2^2

And we deduce that x must be between 1 and 2. But since negative numbers become positive when squared, the numbers between -2 and -1 are also fine. So, the domain is

[-2,-1]\cup [1,2]

Predicates (b) and (d) are identical to (a) and (c)

6 0
2 years ago
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