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2 years ago

12

Am adult ticket at an amusement park cost $24.95 and a child’s ticket costs $15.95. A group of 10 people paid $186.50 to enter t

he park . How many were adults?

2 answers:

kifflom [539]2 years ago

7 0

The correct answer is 4 adults

saveliy_v [14]2 years ago

3 0

there were four adults

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What are the eight-digit grid coordinates for benchmark 86 (circled in red)?

Alex777 [14]

Answer:

An eight-digit grid coordinate gives a precision to the nearest 10 meters

Step-by-step explanation:

Grid coordinates are meant to accurately direct to a specific location, using a map that comes with vertical and horizontal lines of equal spacing and numbers attached to each line to map out a location. The crossing vertical and horizontal lines have unique numbers and form small squares known as grid squares.

The more digits in the coordinate of a point the increase in precision an eight- digit gives a precision to the nearest 10 meters

3 0

2 years ago

If the quantity 4 times x times y cubed plus 8 times x squared times y to the fifth power all over 2 times x times y squared is

MA_775_DIABLO [31]

$\dfrac{4xy^3 + 8x^2y^5 }{2xy^2}$

$= \dfrac{4xy^3(1+2xy^2)}{2xy}$

$= 2y^2(1 + 2xy^2)$

$= 2y^2 + 4xy^4$

Answer: a = 1, b 2, c = 1, d = 4

8 0

1 year ago

What is the value of b and the missing symbol in Jamilla’s inequality?

Sindrei [870]

Answer:

$b=1, \geq$

Step-by-step explanation:

we know that

The absolute value function has two solutions

Observing the graph

the solutions are

$x\geq 1$ and $x\leq -3$

First solution (case positive)

assume the symbol of the first solution and then compare the results

$\left|x+b\right|\ge2$

$(x+b)\ge2$

$x\ge2-b$

$2-b=1\\b=2-1\\ b=1$

Second solution (case negative)

$-(x+b)\ge2$

Multiply by -1 both sides

$(x+b)\leq-2$

substitute the value of b and compare the results

$(x+1)\leq-2$

$x\leq-2-1$

$x\leq-3$ -------> is correct

4 0

2 years ago

Read 2 more answers

Which ordered pairs are solutions to the inequality 2y−x≤−6 ?

Vinil7 [7]

Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied

Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.

Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.

Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.

Solutions are: (1, -4), (0, -3) , (2, -2)

4 0

2 years ago

An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up

Papessa [141]

Answer:

$s(t)=-9.8t^2+49t+58.8$

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form $s(t)=-gt^2+v_0t+h_0$ , where

g = Force of gravity,

$v_0$ = Initial velocity,

$h_0$ = Initial height.

For our given scenario $g=-9.8$ , $v_0=49$ and $h_0=58.8$ . Upon substituting these values in object's height function, we will get:

$s(t)=-9.8t^2+49t+58.8$

Therefore, the function for the height of the arrow would be $s(t)=-9.8t^2+49t+58.8$ .

6 0

2 years ago