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PSYCHO15rus [73]
2 years ago
13

A civil engineer tested concrete samples to investigate the difference in strength, in newtons per square millimeter (N/mm2), be

tween concrete hardened for 21 days and concrete hardened for 28 days. The engineer measured the strength from each sample, calculated the difference in the mean strength between the samples, and then constructed the 95 percent confidence interval, (2.9,3.1), for the difference in mean strengths.
Assuming all conditions for inference were met, which of the following is a correct interpretation of the 95 percent confidence level?

a) In repeated samples of the same size, approximately 95 percent of the samples will yield the interval 2.9 N/mm^2 to 3.1 N/mm^2.

b) In repeated samples of the same size, approximately 95 percent of the sample means will fall between 2.9 N/mm^2 and 3.1 N/mm^2
c)In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will extend from 2.9 N/mm^2 to 3.1 N/mm^2.

d)In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will capture the population difference in means.

e) In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will capture the sample difference in means.
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
3 0

Answer: d)In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will capture the population difference in means.

Step-by-step explanation:

Confidence interval is constructed to estimate a range of values that could possibly contain the population parameter. This could be the population mean or population proportion. A 95 percent confidence interval does not mean 95% probability. It tells how confident that we are that the confidence interval contains the population proportion. If we construct 100 of the given confidence interval, we are confident that 95% of them would contain the true population parameter. Therefore, the correct option is

d)In repeated samples of the same size, approximately 95 percent of the intervals constructed from the samples will capture the population difference in means.

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An account earns simple annual interest.<br><br> $925 at 2.3% for 2.4 years
aksik [14]

Answer:

$51.06

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, 925x0.023=21.275

21.275x2.4=$51.06 in total

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

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5 0
1 year ago
Peter is at a lumber yard. He gets 2 free boxes of nails for every 10 boards he buys. Write an expression for the number of boxe
Sati [7]
A. The number of 10-boards Peter bought is equal to n divided by 10. Then, each of the 10-boxes will get two boxes of nails. The number of boxes of nails that Peter will have after buying n boards will be,

    N = (2)(n/10)

Simplifying,

<em>   N = n/5</em>

b. If the number of boards are 90 then,

     N2 = (90/10)(2)(100 nails/box)
     N2 = 1800

Answer: 1800
7 0
2 years ago
Read 2 more answers
Write an expression that represents the volume of a rectangular prism (box) with length 2003-02-02-00-00_files/i0260000.jpg, wid
k0ka [10]

h=5 in

w-6 in

l=12 in

SA/V=2*12*6+2*6*5+2*12*5/12*6*5

817:180

This is just an example do not use this exact equation and number! Hope it helps. : )
3 0
1 year ago
Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap
Luda [366]

Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

f(x) = 0.5\lambda e^{-\lambda |x|} for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

\lambda=\frac{1}{\beta} and μ = 0.

Standard deviation = √2β

S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424

Now substitute the value of β in \lambda=\frac{1}{\beta}.

\lambda=\frac{1}{28.1424}=0.03553357

Hence, the value of the parameter is λ is 0.03553357

3 0
2 years ago
If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
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