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hodyreva [135]
2 years ago
10

A four-person committee is chosen from a group of eight boys and six girls. If students are chosen at random, what is the probab

ility that the committee consists of all boys? StartFraction 4 Over 1001 EndFraction StartFraction 15 Over 1001 EndFraction
Mathematics
2 answers:
GaryK [48]2 years ago
5 0

Answer:

10/143

Step-by-step explanation:

got 100%

Lapatulllka [165]2 years ago
4 0

Answer: 0.07

Step-by-step explanation:

in the group, we can have only 4 persons.

we have 8 boys, and 6 girls.

We want to find the probability that in the comite we have only boys.

Ok, for the first selection, the probability of selecting a boy is equal to the number of boys divided the total number of the group ( 8 + 6 = 14) this is

p1 = 8/14.

For the second selection we do the same, but we already slected a boy, so now the number of boys is 7, and the total number of posibilities is 13.

p2 = 7/13.

for the third selection we do the same, in this case the probability is

p3 = 6/12

for the fourth selection the probability will be:

p4 = 5/11

The joint probability, of all the events happening at the same time, is equal to the product of the singular probabilities:

P = p1*p2*p3*p4 = (8/14)*(7/13)*(6/12)*(5/11) = 0.07

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Answer:

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Step-by-step explanation:

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If the pointer in the figure is spun twice, find the probability that the pointer lands on red (R) both spins.
r-ruslan [8.4K]

The probability of the pointer lands on red(R) both spin = \frac{1}{36}

Step-by-step explanation:

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Formula

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For the answer to the question above, 
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<span>You can also check this by plugging in values: </span>

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