1/2 of the cake was eaten
1+2=3. 3/6=1/2
All the slices are the same size
1) 26 different outcomes are in the sample space.
2) 1 / 26 is the probability that the computer produces the first letter of your first name.
<u>Step-by-step explanation:</u>
<u>1) You have to find out the different outcomes in the sample space :</u>
- A "Sample space" is defined as the set of all the possible outcomes of an event.
- Here, the given event is randomly selecting a letter from the alphabets.
Therefore, the sample space must contain all the possible alphabets that can be chosen randomly.
The sample space is the set of all the 26 alphabets in English language.
⇒ Sample space = {A,B,C,D...........,Y,Z}
⇒ 26 different outcomes.
<u>2) The probability the computer produces the first letter of your first name :</u>
Here, the required outcome is getting the first letter of your first name.
Probability = No. of required outcomes / total no. of outcomes.
For example, The name Alex Davis has the first letter of the fist name as alphabet 'A'.
∴ Probability = 1 / 26
Similarly, for any first name there is going to be any one alphabet from the 26 alphabets, thus the probability to get the first letter will be always 1 / 26.
Average speed is the total distance traveled by an object at a certain period of time. To calculate for the average speed we divide the total distance covered by the total time. We do as follows:
Average speed = 560 meters / 25 seconds = 22.4 m/s
Answer:
The probability of hitting the bullseye at least once in 6 attempts is 0.469.
Step-by-step explanation:
It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.
The probability of hitting bullseye in each attempt, p = 0.10
The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90
Let x be the event of hitting the bullseye.
We need to find the probability of hitting the bullseye at least once in 6 attempts.
.... (1)
According to binomial expression
where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.
The probability that the dart thrower not hits the bullseye in 6 attempts is
Substitute the value of P(x=0) in (1).
Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.
Answer:
we kind of need to see the diagram
Step-by-step explanation:
