Answer:
The regression equation for the winter rainy days is "Humidity = (β0 + β5) + β1Temperature".
Step-by-step explanation:
Given:
Humidity = β0 + β1Temperature + β2Spring + β3Summer + β4Fall + β5Rain + ε ...........(1)
Since there can be only one of spring, summer,fall, and winter at a point in time or in a season, we will have the following when there are winter rainy days:
Spring = 0
Summer = 0
Fall = 0
Rain = 1
Substituting all the relevant values into equation (1) and equating ε also to 0, a reduced form of equation (1) can be obtained as follows:
Humidity = β0 + β1Temperature + (β2 * 0) + (β3 * 0) + (β4 * 0) + (β5 * 1) + 0
Humidity = β0 + β1Temperature + 0 + 0 + 0 + β5 + 0
Humidity = (β0 + β5) + β1Temperature
Therefore, the regression equation for the winter rainy days is "Humidity = (β0 + β5) + β1Temperature".
Total number of people = 125 + 100 = 225
Number of males = 100
Set as ratio
100:225
Simplify to 4:9 (can not simplify further without having decimals but you can’t have half a person)
-82.5, -41 4/5, -13 1/8, -4.3
So if one bit of the length, is half the size of the other bit then we can make the following equation, for x being the length of rope:
x + 2x = 66
3x = 66
x = 22
That is the length, of the smaller one (half the big one), so 2x = 44. Hence d) is your answer.
Hope I helped!
Answer:1. C 3. 52
Step-by-step explanation:
