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1 year ago

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Clint is in study hall reading the hunger games after 20 minutes he is on page 151 after 45 minutes he's on page 181 how many pa

ges had Klint red prior to study hall

1 answer:

Mademuasel [1]1 year ago

6 0

After 20 minutes Clint is on page = 151

After 45 minutes Clint is on page = 181

Time slot = $45-20=25$ minutes

Difference in pages in 25 minutes = $181-151=30$ pages.

Lets suppose Clint is reading each page at same pace.

So , In 25 minutes, he can read = 30 pages

In 1 minute he can read = $\frac{30}{25}=1.2$ pages

Initial time is 20 minutes, so he can read the number of pages in 20 minutes = $20\times1.2=24$

So, number of pages Clint read prior to study hall were =

$151-24=127$ pages.

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Mark has three 4 1/2 oz cans and five 8 1/4 oz cans. How many ounces of tomatoes does Mark need?

Mashutka [201]

Answer:

54.74 ounces of tomatoes mark need.

Step-by-step explanation:

Given : Mark has three $4\frac{1}{2}$ oz cans and five $8\frac{1}{4}$ oz cans.

To find : How many ounces of tomatoes does Mark need?

Solution :

Mark has three $4\frac{1}{2}$ oz cans.

i.e. $3\times 4\frac{1}{2}=3\times \frac{9}{2}=\frac{27}{2}$

Mark has five $8\frac{1}{4}$ oz cans.

i.e. $5\times 8\frac{1}{4}=5\times \frac{33}{4}=\frac{165}{4}$

Total ounces of tomatoes does Mark need is

$T=\frac{27}{2}+\frac{165}{4}$

$T=\frac{54+165}{4}$

$T=\frac{219}{4}$

$T=54.75$

Therefore, 54.74 ounces of tomatoes mark need.

7 0

1 year ago

n 2019, approximately 97.4% of all the runners who started the Boston Marathon (in Boston, Massachusetts, USA) were able to comp

Zarrin [17]

Answer:

0.1199 = 11.99% probability that at least 5 of them did not finish the marathon

Step-by-step explanation:

For each runner, there are only two possible outcomes. Either they finished the marathon, or they did not. The probability of a runner completing the marathon is independent of any other runner. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

97.4% finished:

This means that 100 - 97.4 = 2.6% = 0.026 did not finish, which means that $p = 0.026$

100 runners are chosen at random

This means that $n = 100$

Find the probability that at least 5 of them did not finish the marathon

This is:

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{100,0}.(0.026)^{0}.(0.974)^{100} = 0.0718$

$P(X = 1) = C_{100,1}.(0.026)^{1}.(0.974)^{99} = 0.1916$

$P(X = 2) = C_{100,2}.(0.026)^{2}.(0.974)^{98} = 0.2531$

$P(X = 3) = C_{100,3}.(0.026)^{3}.(0.974)^{97} = 0.2207$

$P(X = 4) = C_{100,4}.(0.026)^{4}.(0.974)^{96} = 0.1429$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0718 + 0.1916 + 0.2531 + 0.2207 + 0.1429 = 0.8801$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.8801 = 0.1199$

0.1199 = 11.99% probability that at least 5 of them did not finish the marathon

4 0

1 year ago

A movie theater was putting up their posters in the frames they had installed on the wall for upcoming attractions. They have 8

Serjik [45]

Answer:

1680

Step-by-step explanation:

Since there are 4 places (frames) to put up each poster, we think individually:

In the first place they can place ANY OF THE 8 POSTERS

In 2nd place, they can place ANY OF THE REMAINING 7 POSTERS

In 3rd place, they can place ANY OF THE REMAINING 6 posters

and

in last place, they can place ANY OF THE REMAINING 5 posters

The number of ways is the multiplication of them all, so:

8 * 7 * 6 * 5 ways = 1680 ways

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2 years ago

Read 2 more answers

Karina solves the system using linear combination and arrives at the equation 116y = 96.28. She then solves this equation for y.

igomit [66]

116y =96.28
116y = 96.28
---- ---------
116 116

y = .83

5 0

1 year ago

Which of the equations below could be the equation of this parabola?

Vilka [71]

Answer:

B

Step-by-step explanation:

Parabola that is opening upward has the form $y=ax^2$
Parabola opening downward has the form $y=-ax^2$
Parabola opening leftward has the form $x=-ay^2$
Parabola opening rightward has the form $x=ay^2$

Where a is a constant

Now, looking at the graph given, it takes the form $x=-ay^2$

Where a is 3 (matching the answer).

Hence, B is the correct answer choice.

7 0

2 years ago