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Studentka2010 [4]
2 years ago
9

A poll conducted a week before the school election to the student council showed that Janice would win with 63% of the vote. The

margin of error was 14%. If Janice needs to receive at least half the votes to win the election, can we be confident of Janice's victory?
Mathematics
1 answer:
k0ka [10]2 years ago
8 0

OPTIONS:

No, because she could receive as low as 14% of the vote.

No, because she could receive as low as 49% of the vote.

Yes, because she could receive as much as 77% of the vote.

Yes, because the poll stated that she will win with 63% of the vote.

Answer:

No, because she could receive as low as 49% of the vote.

Step-by-step explanation:

Given that:

Poll suggestion = 63%

Margin of Error (E) = 14%

This means that; the range or interval in which the vote obtained could fall would be ;

Poll suggestion ± margin of Error

63% ± 14%

Lower bound attainable = (63% - 14%) = 49%

Upper bound attainable = (63% + 14%) = 77%

Since, winning actually requires obtaining atleast half of the votes (that is 50%) ; and suggested poll suggested votes could fall as low as 49% ; then Janice can't be so confident of victory.

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alina1380 [7]

Answer:

0

Step-by-step explanation:

Each expression is a way to write the sum ...

3 + 5 + 7 + 9

That sum in each case is 24, so the difference is 24-24 = 0.

6 0
2 years ago
A formula calls for 0.6 mL of a coloring solution. Using a 10-mL graduate calibrated from 2 to 10 mL in 1-mL units, how could yo
MrMuchimi

Answer:

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

or

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

Step-by-step explanation:

Given:

formula calls for 0.6 mL of a coloring solution

10-mL graduate calibrated from 2 to 10 mL in 1-mL units

Now,

We want to use an aliquot technique to measure 0.6 ml of coloring solution.

Because the calibrated graduate is used to measure 2ml to 10ml with 1ml as unit measure

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

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or

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

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3 0
2 years ago
Which equation correctly applies the law of cosines to solve for an unknown angle measure?
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The law of cosines is:
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2 years ago
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(a) 4 
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tankabanditka [31]

Seems like it would be

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7 0
2 years ago
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