jared has mowed 2/5 of the yard abby says that jason has mowed 4/6 of the yard is abby correct EXPLAIN

When you divide a whole number by a decimal less than 1, the quotient is greater than the whole number. why?

Viktor [21]

Well if you get back to the definition of a division, diving X by Y is finding out how many Ys you can have in a X.

It is clear that you will have more than X times Y if Y is less than 1 since dividing X by 1 is exactly X.

If you think of 10 and 1, you can divide 10 in exactly 10 portions of 1.
But you can divide it into 100 portions of 0,1.
And 100 is bigger than 10 of course.
Hope this helps.

4 0

2 years ago

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A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year

uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that $p = 0.8$ .

10 students, so $n = 10$

We have to find:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684$

$P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074$

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758$

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that $p = 0.3758$

Two groups, so $n = 2$

We have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691$

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0

2 years ago

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Maggie needs to spend at least six hours each week practicing the piano. She has already practiced three and one fourth hours th

Marta_Voda [28]

Let X equal the remaining time she needs to practice.

You would have 2x

The combined total needs to be 6 hours or greater.

You need to add the amount she already practiced to 2x.

Now you have: three and one fourth + 2x

This needs to be greater than or equal to 6.

Answer: three and one fourth + 2x ≥ 6

8 0

2 years ago

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A print shop purchases a new printer for $25,000. The equipment depreciates at a rate of 5% each year. The relationship between

Pani-rosa [81]

Answer:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

$y(x) = 25,000*0.95^x$

In the first year the value of the printer is:

$y(1) = 25,000*0.95^1 = 23,750$

On the second year the value of the printer is:

$y(2) = 25,000*0.95^2 = 22,562.5\\$

On the third year the value of the printer is:

$y(3) = 25,000*0.95^3 = 21,434.38\\$

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

5 0

2 years ago

21. In your day-to-day routines, you likely use measurement to cook or do home renovations, such as adding new tile flooring. Ho

sergij07 [2.7K]

Answer:

Depending of the exact career but measurements are plentiful in the healthcare business.

First, you'll most likely deal with weight and height... since that's part of most health care consultations.

Then, if you deal with medication, you'll use grams, milligrams, milliliters, liters all the time. depending if the medication is in solid or liquid form.

Even as a nutritionist, you'll deal with grams and such for portion sizes.

There are countless of ways you'll use maths and measurements in the healthcare sector.

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2 years ago

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