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Jet001 [13]
2 years ago
6

The two conditional relative frequency tables show the results of a neighborhood survey on the number and types of gardens in th

e community.
A 4-column table with 3 rows titled garden-type frequencies by column. The first column has no label with entries flower garden, no flower garden, total. The second column is labeled vegetable garden with entries 0.28, 0.72, 1.0. The third column is labeled no vegetable garden with labels 0.22, 0.78, 1.0. The fourth column is labeled total with entries 0.25, 0.75, 1.0.
Table B: Garden-Type Frequencies by Row

A 4-column table with 3 rows titled garden-type frequencies by row. The first column has no label with entries flower garden, no flower garden, total. The second column is labeled vegetable garden with entries 0.56, 0.48, 0.5. The third column is labeled no vegetable garden with labels 0.44, 0.52, 0.5. The fourth column is labeled total with entries 1.0, 1.0, 1.0.
Which table could be used to answer the question "Assuming someone has a flower garden, what is the probability they also have a vegetable garden?"

Table A, because the given condition is that the person has a flower garden.
Table A, because the given condition is that the person has a vegetable garden.
Table B, because the given condition is that the person has a flower garden.
Table B, because the given condition is that the person has a vegetable garden.
Mathematics
2 answers:
Igoryamba2 years ago
8 0

Answer:

The answer is C.

Step-by-step explanation:

Ivenika [448]2 years ago
3 0

Answer:

C

Step-by-step explanation:

if youre looking on edge then yeah

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2.314 divided by 1.3
kirza4 [7]
1.78 is the correct answer.
5 0
2 years ago
Which is the largest: 27/30, 28/32, 38/40, 36/39, 75/85
sleet_krkn [62]
I believe the answer is 27/30
3 0
2 years ago
Read 2 more answers
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

Area = 128

Let the dimension of the paper be x and y;

Such that:

Length = x

Width = y

So:

Area = x * y

Substitute 128 for Area

128 = x * y

Make x the subject

x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

Width = y + 4

The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

A' = -512y^{-2} + 2

Set

A' = 0

This gives:

0 = -512y^{-2} + 2

Collect Like Terms

512y^{-2} = 2

Multiply through by y^2

y^2 * 512y^{-2} = 2 * y^2

512 = 2y^2

Divide through by 2

256=y^2

Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

Recall that the new dimensions are:

Length = x + 2

Width = y + 4

So:

Length = 8 + 2

Length = 10

Width = 16 + 4

Width = 20

To double-check;

Differentiate A'

A' = -512y^{-2} + 2

A" = -2 * -512y^{-3}

A" = 1024y^{-3}

A" = \frac{1024}{y^3}

The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0
1 year ago
A company that manufactures small canoes has a fixed cost of $ 18 comma 000$18,000. It costs $ 120$120 to produce each canoe. Th
Scilla [17]
If the company makes 1 canoe only, then the cost is, the fixed cost plus how much it costs for the 1 canoe, or
180,000 + 1*120

if it makes 2 canoes
180,000 + 2*120
3 canoes   180,000 + 3*120
4canoes   180,000 + 4*120
x canoes  180,000 + x*120

so... we dunno what "x" is, but whatever "x" maybe, the cost ends up as 180,000 + x*120, or 180,000 + 120x

now, let's see the revenue
1 canoe 1 * 240
2 canoes 2*240
3 canoes 3*240
x canoes x*240

so.. whatever "x" maybe, the Revenue is x*240 or 240x

break-even point is when, the amount of expenses and earnings cancel each other out, or, there's no profit, but there's no loss either, same amount that's spent is also earned back

so, the break-even point occurs when Revenue = Cost

180,000 + 120x = 240x     <--- solve for "x"
4 0
2 years ago
In an article in Statistics and Computing [""An Iterative Monte Carlo Method for Nonconjugate Bayesian Analysis"" (1991, pp. 119
Marina CMI [18]

Answer:

Step-by-step explanation:

Hello!

a)

The dependent variable is

Y: length of a dugong

The explanatory variable is

X: age of a dugong

You need to estimate the linear regression of the length of the dugongs as a function of their age.

Using the given data I've estimated the regression using a statistic software:

The regression model is E(Yi)= α + βXi

The estimated model is ^Yi= a + bXi

Where a is the estimate of the intercept and b is the estimate of the slope:

a= 2.02

b= 0.03

And the estimate of the population variance of the error is Se²= 0.03

The estimated regression equation is ^Yi= 2.02 + 0.03Xi

b)

You have to estimate the length of a dugong when its age is 11 years using the model, for this all you have to do is replace X=11 in the regression line and calculate the corresponding ^Y value:

^Yi= 2.02 + 0.03*11= 2.35

The average length of an 11-year-old dugong should be 2.35.

I hope it helps!

5 0
2 years ago
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