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2 years ago

AX and EX are secant segments that intersect at point X. What is the length of DE?

Mathematics

2 answers:

vazorg [7]2 years ago

5 0

Answer:

we kind of need to see the diagram

Step-by-step explanation:

quester [9]2 years ago

5 0

Answer: 3 units

Step-by-step explanation:

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A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. A fre

JulsSmile [24]

Answer:

SD = 7588.09

Step-by-step explanation:

Check the distribution table attached to for the step by step solution:

The formula for the mean, $\bar{x} = \frac{\sum fx}{\sum f}$

$\bar {x} = \frac{1410040}{80} \\\bar {x} = 17625.5$

The variance , $V(X) = \sqrt{\frac{\sum f(x - \bar{x}^2)}{n-1} }$

$V(X) = \frac{4548750000}{80 - 1} \\V(X) = 57579113.92$

Standard Deviation,

$SD = \sqrt{V(X)} \\SD = \sqrt{57579113.92}$

SD = 7588.09

7 0

2 years ago

Read 2 more answers

Circle E has a radius of 40 inches with = 324°. Find the exact length of

Anni [7]

Let the arc is ABC with angle 324 degree, to find the length of that arc follow the steps;
The circumference of the circle E is :C = 2 r π
C = 2 * 40 π = 80 π cm.
Also 324° / 360° = 0.9m Arc (ABC ) = 0.9 * 80 π = 72 π cm
There is also formula for calculating the measure of an arc:
m Arc = r π α / 180°
m Arc = 40 π * 324 / 180
= 40π * 1.8 = 72 π
Now we have to find the exact length ( π ≈ 3.14 )
m Arc ( ABC ) = 72 * 3.14 = 226.08 cm

8 0

2 years ago

Read 2 more answers

Mateus’s bank issued an advertisement saying that 90\%90%90, percent of its customers are satisfied with the bank’s services. Si

densk [106]

Answer:

The probability of getting a sample with 80% satisfied customers or less is 0.0125.

Step-by-step explanation:

We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.

Let $\hat p$ = sample proportion of satisfied customers

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion of satisfied customers = 90%

n = sample of customers = 80

Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( $\hat p \leq$ 80%)

P( $\hat p \leq$ 80%) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\leq$ $\frac{0.80-0.90}{\sqrt{\frac{0.80(1-0.80)}{80} } }$ ) = P(Z $\leq$ -2.24) = 1 - P(Z < 2.24)

= 1 - 0.9875 = 0.0125

The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.

8 0

2 years ago

The sum of 5x2y and (2xy2 + x2y) is

allochka39001 [22]

5x²y + 2xy² + x²y

Combining like terms would be
6x²y + 2xy²

The two terms are now unique and cannot be combined any further.

6 0

1 year ago

Given: Circle X with a Radius r and circle Y with radius s Prove: Circle x is similar to circle y

lana [24]

Two figures are similar if one is the scaled version of the other.

This is always the case for circles, because their geometry is fixed, and you can't modify it in anyway, otherwise it wouldn't be a circle anymore.

To be more precise, you only need two steps to prove that every two circles are similar:

Translate one of the two circles so that they have the same center
Scale the inner circle (for example) unit it has the same radius of the outer one. You can obviously shrink the outer one as well

Now the two circles have the same center and the same radius, and thus they are the same. We just proved that any two circles can be reduced to be the same circle using only translations and scaling, which generate similar shapes.

Recapping, we have:

Start with circle X and radius r
Translate it so that it has the same center as circle Y. This new circle, say X', is similar to the first one, because you only translated it.
Scale the radius of circle X' until it becomes $s$ . This new circle, say X'', is similar to X' because you only scaled it

So, we passed from X to X' to X'', and they are all similar to each other, and in the end we have X''=Y, which ends the proof.

8 0

2 years ago

Read 2 more answers