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2 years ago

AX and EX are secant segments that intersect at point X. What is the length of DE?

Mathematics

2 answers:

vazorg [7]2 years ago

5 0

Answer:

we kind of need to see the diagram

Step-by-step explanation:

quester [9]2 years ago

5 0

Answer: 3 units

Step-by-step explanation:

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HELP ME!! PLEASE ASAP

saul85 [17]

Answer:I am giving out 60 points if answer my question s

Step-by-step explanation:

Plz help

3 0

2 years ago

Read 2 more answers

In ΔMNO, the measure of ∠O=90°, ON = 65, MO = 72, and NM = 97. What is the value of the tangent of ∠M to the nearest hundredth?

PilotLPTM [1.2K]

Answer:

Therefore the value of tangent of ∠ $M$ is $42$ °.

Step-by-step explanation:

Given that,

In Δ $MNO$ , ∠ $O=90$ °, $ON=65,$ $MO=72,$ and $NM=97.$

and we have to find the value of tangent of ∠ $M.$

Diagram of the given triangle is shown below:

Now,

Δ $MNO$ is a right angle triangle, so we can use all the trigonometric ratio.

$sin\alpha =\frac{Perpendicular}{Hypotenuse}$

$cos\alpha =\frac{Base}{Hypotenuse}$

$tan\alpha =\frac{sin\alpha }{cos\alpha }$ = $\frac{Perpendicular}{Base}$

tangent of ∠ $M$ = $\frac{Perpendicular}{Base}$

= $\frac{ON}{MO}$

= $\frac{65}{72}$

= $0.90278$

∴∠ $M$ = $tan^{-1} (0.90278)$

= $42.0750$ ° ≅ $42$ °

Therefore the value of tangent of ∠ $M$ is $42$ °.

4 0

2 years ago

Marc mows lawns for $25 each lawn, plus $5 for every hour he spends mowing. The equation for his total earnings per lawn is y =

Mila [183]

Answer:

<h2>The flat pay $25 represents the intercept</h2>

Step-by-step explanation:

To answer this question we need to first understand and compare it with the equation of straight line.

i.e $y= mx+c$ which is the equation of line

where m= slope

y= dependent variable

x= independent variable

c= intercept

Given

$y= 25+5h$

comparing both expression we can see that

25 corresponds to c which is the intercept

6 0

2 years ago

Pq=6x+25 and qr=16-3x; find pr

Viktor [21]

$Given:\\\overline{PQ}=6x+25\\\overline{QR}=16-3x\\\\Finding:\overline{PR}$

$If \; Q \; is \; a \; point \; in \; between \; the \; line \; segment \; \overline{PR}, \; \\ then \; the \; distance \; of \; line \; segment \; \overline{PR} \; \\ can \; be \; found \; by \; adding \; line \; segment \; \overline{PQ} \; and \; \overline{QR}.$

$Using \; the \; concept \; \overline{PQ}+\overline{QR}=\overline{PR} \;,\\ we \; need \; to \; set \; up \; an \; equation \; given \; below:$

$\overline{PR} =6x+25 +16-3x\\\\Step \; 1: Grouping \; Like \; Terms\\\overline{PR} =6x-3x+25 +16\\\\Step \; 2: Combining \; Like \; Terms\\\overline{PR} =3x+41$