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1 year ago

Pq=6x+25 and qr=16-3x; find pr

Mathematics

2 answers:

Nitella [24]1 year ago

8 0

Answer:

PR = 3x + 41

Step-by-step explanation:

Given

PQ = 6x + 25

QR = 16 - 3x

Q is the common point on the line PR, thus dividing PR into PQ and QR.

Therefore, we can write,

PR = PQ + QR

PR = 6x + 25 + 16 - 3x

PR = 6x- 3x + 25 + 16

PR = 3x + 41

Therefore, PR = 3x + 41

Viktor [21]1 year ago

3 0

$Given:\\\overline{PQ}=6x+25\\\overline{QR}=16-3x\\\\Finding:\overline{PR}$

$If \; Q \; is \; a \; point \; in \; between \; the \; line \; segment \; \overline{PR}, \; \\ then \; the \; distance \; of \; line \; segment \; \overline{PR} \; \\ can \; be \; found \; by \; adding \; line \; segment \; \overline{PQ} \; and \; \overline{QR}.$

$Using \; the \; concept \; \overline{PQ}+\overline{QR}=\overline{PR} \;,\\ we \; need \; to \; set \; up \; an \; equation \; given \; below:$

$\overline{PR} =6x+25 +16-3x\\\\Step \; 1: Grouping \; Like \; Terms\\\overline{PR} =6x-3x+25 +16\\\\Step \; 2: Combining \; Like \; Terms\\\overline{PR} =3x+41$

Conclusion:

$\overline{PR} \; is \; represented \; the \; expression \; 3x +41$

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A force of 500.0 is represented graphically with its tail at the origin and the tip pointed in a direction 30.0° above the posit

trapecia [35]

Answer:

$F^{'}=(250\sqrt{3},250 })$

Step-by-step explanation:

We have F´ =500 and $\alpha$ =30º, so x and y components:

F´ = $(F_{x} , F_{y})$ this is

$F_{x} = F^{'} *Cos\alpha$

$F_{y} = F^{'} *Sin\alpha$

$F_{x} = F`*Cos\alpha =500*Cos30=500*\frac{\sqrt{3} }{2} =250\sqrt{3}$

$F_{y}=F*Sin\alpha =500*Sin30=500*\frac{1}{2}=250$ ;

Finally

F' = $(250\sqrt{3} , 250)$

3 0

2 years ago

What number would you multiply the second equation by in order to eliminate the x-terms when adding to the first equation? What

alexandr402 [8]

Answer:

1. Multiply (2) by 2 to eliminate the x-terms when adding

2. Multiply (2) by 3 to eliminate the y- term

Step-by-step explanation:

Use this system of equations to answer the questions that follow.

4x-9y = 7

-2x+ 3y= 4

what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 2 to eliminate the x-terms when adding the first equation

4x-9y = 7

-4x +6y = 8

Adding the equations

4x + (-4x) -9y + 6y = 7 + 8

4x - 4x - 3y = 15

-3y = 15

y = 15/-3

= -5

what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?

4x-9y = 7 (1)

-2x+ 3y= 4 (2)

Multiply (2) by 3 to eliminate the y- term

4x - 9y = 7

-6x + 9y = 12

Adding the equations

4x + (-6x) -9y + 9y = 7 + 12

4x - 6x = 19

-2x = 19

x = 19/-2

= -9.5

x = -9.5

6 0

1 year ago

Read 2 more answers

In a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979,

Fed [463]

Answer:

we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

Step-by-step explanation:

Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.

Let X be the group married less than 2 years and Y less than 5 years

X Y Total

Sample size 300 300 600

Favouring 240 288 528

p 0.8 0.96 0.88

$H_0: p_x=p_y\\H_a: p_x>p_y$

p difference = -0.16

Std error for difference = $\sqrt{0.88*0.12/600} =0.01327$

Test statistic = p difference/std error=-6.03

p value <0.000001

Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

4 0

2 years ago

Given the image below, what is the image of C after a dilation with a scale factor of 3

Ne4ueva [31]

Answer: The coordinates of point C after the dilation are (-2, 5)

Step-by-step explanation:

I guess that you want to find where the point C ends after the dilation.

Ok, if we have a point (x, y) and we do a dilation with a scale A around the point (a,b), then the dilated point will be:

(a + A*(x - a), b + A*(y - b))

In this case we have:

(a,b) = (2,1) and A = 3.

And the coordinates of point C, before being dilated, are: (1, 2)

Then the new location of the point C will be:

C' = (1 + 3*(1 - 2), 2 + 3*(2 - 1)) = (1 -3, 2 + 3) = (-2, 5)

6 0

2 years ago

A machine is set to fill the small-size packages of m&m candies with 56 candies per bag. a sample revealed: three bags of 56

luda_lava [24]

In statistics, the amount of degrees of freedom is the quantity of values in the final computation of a statistic that are free to differ. In this case, you can get the answer by adding the number of bags and subtracting 1.

So in computation, this would look like: 3 + 2 + 1 + 2 - 1 = 7

Therefore, 7 is the degrees of freedom.

7 0

1 year ago