All categories

2 years ago

What is the value of s and the length of side BC if ABCD is a rhombus?

Mathematics

2 answers:

OverLord2011 [107]2 years ago

5 0

The rhombus has four equal sides

10s - 16 = 9s + 29
10s - 9s = 29 + 16
s = 45

BC = CD = 10s-16 = 10*45 - 16 = 434

Natali5045456 [20]2 years ago

4 0

Step 1

<u>Find the value of s</u>

we know that

In a Rhombus all sides are congruent

$AB=BC=CD=DA$

$AB=9s+29\\CD=10s-16$

equate AB and CD

$9s+29=10s-16\\$

Combine like term

$10s-9s=29+16\\$

$s=45\ units$

<u>The answer Part a) is</u>

the value of s is $45\ units$

Step 2

<u>Find the value of side AB</u>

$AB=9s+29$

substitute the value of s

$AB=9*45+29=434\ units$

Remember that the sides are congruent

$AB=BC=CD=DA$

therefore

<u>the answer Part b) is</u>

The length of the side BC is $434\ units$

You might be interested in

Why does duffer Mcvolt want lights strung around the golf course

sertanlavr [38]

He really enjoys swinging nightclubs

4 0

2 years ago

Amber believes triangle ABC and triangle GFE are congruent. She has recorded the measures of some of the angles and the lengths

Nostrana [21]

If the triangles are congruent, the angle opposite the 32 cm side will have the same measure as angle E, 40°. An appropriate choice for this question is ...
b. The measure of c is 40.

_____
In actual fact, the triangles not only are not congruent, they cannot exist. The total of sides FG and FE (82 cm) is less than the length of side GE (38 in). 82 cm is about 32.3 inches, about 5.7 inches too short.

Even if you overlook the units problem, the sum of squares of the sides of the triangle is 32² +38² = 2468, somewhat short of 50² = 2500. That is, the largest angle is slightly more than 90°. It is closer to 90.754° ≈ 91°.

You can label a diagram any way you want, but that doesn't mean the numbers are consistent or sensible.

6 0

2 years ago

Read 2 more answers

Meteorologists look for weather trends across US states in the same geographical region. Kentucky and Illinois share a border. T

olya-2409 [2.1K]

The average annual temperatures (°F) from 1991 to 2000 for Kentucky were 57.5, 55.1, 52.2, 55.6, 55.6, 54.4, 54.5, 58.3, 57.3, and 55.7.

We have to evaluate the measures of center.

Firstly, we will calculate the mean.

Mean = (Sum of all the observations)/ (Total number of observations)

Mean = $\frac{57.5+55.1+52.2+55.6+55.6+54.4+54.5+58.3+57.3+55.7}{10}$