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Mars2501 [29]
2 years ago
11

In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66. What

is the 65th percentile?
Mathematics
2 answers:
enyata [817]2 years ago
6 0

Answer:The 65th percentile is 74

Step-by-step explanation:

The total number of scores sampled is 10. So n = 10

We want to determine the 65th percentile. First step is to rearrange the scores in an increasing order. It becomes

65, 66, 67, 68, 71, 73, 74, 77, 77, 77

Next step is to determine the index by multiplying 65% by n. It becomes

65/100×10 = 6.5. Rounding up to the nearest whole number, it becomes 7

The 65th percentile will be the 7th term from the left. It becomes

74

julia-pushkina [17]2 years ago
4 0

Answer:

The 65th percentile is between 73 and 74

Step-by-step explanation:

Rearrange the ungrouped data in ascending order: 65,66,67,68,71,73,74,77,77,77

The 65th percentile is 65/100 of N ( N = 10) = 65/100 × 10 = 6.5

The 65th percentile is the 6.5th term. The 6th term is 73 and the 7th term is 74, the 6.5th term is between the 6th and 7th term

The 65th percentile is between 73 and 74

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Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0
1 year ago
James has 6 stamps in his stamp collection. Roy has 12 stamps in his stamp collection. James adds 2 stamps to his stamp collecti
hichkok12 [17]
8 to 12, or if simplified, 2 to 3
8 0
1 year ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) P(X \leq 8) = 0.932 (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032 (cumulative)

(d) P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 (cumulative)

(e) P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251

5 0
2 years ago
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
1 year ago
The height of a cone-shaped statue is 9 ft, and the diameter is 12 ft.
gladu [14]
To find the volume of a cone do
\pi \times  {r}^{2}  \times h \div 3
\pi \times 6 \times 6 \times 9 \div 3 = 339.12
answer = 339.12 {ft}^{3}
8 0
1 year ago
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