Circumference = 2πr
Given that circumference 0s 6π, find radius:
2πr = 6π
r = 6π ÷ 2π = 3
Now that we know that the radius is 3 yard, find area:
Area = πr²
Area = π(3)²
Area = 9π = 28.27 yd²
Answer: 28.27 yd²
Check the first picture below.
now, the exercise states to get it from the graph, so we have to graph it first.
Check the second picture below.
recall, the height in feet is on the y-axis, and the time in seconds is on the x-axis.
and rounded up to the nearest tenth will be 0.6.
In this question there are several important information's worth noting.Based on these information's the answer can be easily found. It is given that the total capacity of the tank is 24000 gallons. in 24 hours or in 1 day the amount of water used is 650 gallons. The question requires us to find the time it will take to use 2/3 rd of the water in the tank.
then
2/3 rd water in respect to total water in tank = (2/3) * 24000
= 16000
So 2/3 rd water of full tank is equivalent to 16000 gallons.
Now
650 gallons of water is used in = 24 hours
So
16000 gallons of water will be used in = (24/650) * 16000
= 590.77 hours
So it will take 590.77 hours to consume 2/3rd of the total water present in the tank.
Answer:
1900 meters
Step-by-step explanation:
He ran for 850 meters
Walked for 2.75 kilometers, and that's 2.75 * 1000 meters, which is 2750 meters
The total he walked more than he ran is 2750 - 850 = 1900 meters
Given : tan 235 = 2 tan 20 + tan 215
To Find : prove that
Solution:
tan 235 = 2 tan 20 + tan 215
Tan x = Tan (180 + x)
tan 235 = tan ( 180 + 55) = tan55
tan 215 = tan (180 + 35) = tan 35
=> tan 55 = 2tan 20 + tan 35
55 = 20 + 35
=> 20 = 55 - 35
taking Tan both sides
=> Tan 20 = Tan ( 55 - 35)
=> Tan 20 = (Tan55 - Tan35) /(1 + Tan55 . Tan35)
Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1
=> Tan 20 = (Tan 55 - Tan 35) /(1 + 1)
=> Tan 20 = (Tan 55 - Tan 35) /2
=> 2 Tan 20 = Tan 55 - Tan 35
=> 2 Tan 20 + Tan 35 = Tan 55
=> tan 55 = 2tan 20 + tan 35
=> tan 235 = 2tan 20 + tan 215
QED
Hence Proved
