Simplifying the given expressions we proceed as follows:
(5sqrt3)^x
=5^x*(3^1/2)^x
=5^x*3^x/2
=5^x3^u
where u=x/2
(1/2)^(x-3)
=1/2^(x-3)
=2^-(3-x)
=2^u
where u=-(3-x)
9/3sqrt(3)
=3/(3)^(1/2)
=3(3)^(-1/2)
16/(3sqrt (2^x))
=1/3*(2^4*2^(-x/2))
=1/3*2^(4-x/2)
=1/3*2^u
where:
u=4-x/2
Answer:
2.35 miles
Step-by-step explanation:
Please find the attachment for visual understanding.
We are told that the library is 1.75 miles directly north from the school and the park is 0.6 miles directly south of the school.
To find distance between library and park we will add distance of library from school to the distance of park from school.
Therefore, library is 2.35 miles away from park.
The unknown side is 9. Because 9 x 5= 45, 45 being the perimeter, that is 5 times the unknown side. And 45 is the sum of 9, 16, and 20.
Given the equation p = 3(s + 100)/4
Where,
p = profit made
s = sales
Solving for s from the given equation
p = 3(s + 100)/4
Multiply both sides by 4
4p = 3(s + 100)
4p = 3s + 300
Subtract 300 from both sides of the equation
4p – 300 = 3s
Same as, 3s = 4p – 300
s = (4p – 300)/3
OR, s = 4p/3 – 100
If any of these two is in the options, it’s the right answer.
4 is the only factor common among all terms
