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Angelina_Jolie [31]
2 years ago
11

Daniel Potter bought a new car for $20,000.00. Two years later, he wanted to sell it. He was offered $14,650.00 for it. If he so

ld it for that amount, what was his depreciation rate?
Mathematics
2 answers:
olga_2 [115]2 years ago
5 0
Answer: 13.375% per year

Explanation:

1) Depreciation is the loss of value: $ 20,000.00 - $ 14,650.00 = $ 5,350

2) The percent of depreciation is amount of the depreciation divided by the value of the car when purchased, times 100.

That is (5,350 / $ 20,000) * 100 = 26.75 %

2) The rate is percent of depreciation per year:

depreciation rate = % of depreciation / number of years = 26.75%  / 2 = 13.375% per year.
Oksana_A [137]2 years ago
5 0
First compute the different of the price like this:
 $20,000.00-$14,650.00=5350$<span>
Then divide like this:
</span>\frac{5350.00}{20,000}=75
Now compute the percentage like this:
0,26\times100=26.75\%
In order to compute the rate, divide by the number of years we get:
\dfrac{26.75}{2}=13.37\%
The rate of depreciation is 13.37\%. 
<span>

</span>
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LekaFEV [45]

Answer:

Question 1. (2.2, -1.4)

Question 2. (1.33, 1)

Step-by-step explanation:

Equations for the given lines are

-----(1)

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This equation passes through (0, -3) and (2.2, -1.4).

Now we have to find a common point through which these lines pass or solution of these equations.

From equations (1) and (2),

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From equation (2),

y = -1.4

Therefore, solution of these equations is (2.2, -1.4).

Question 2.

The given equations are y = 1.5x - 1 and y = 1

From these equations,

1 = 1.5x - 1

1.5x = 2

x =

Therefore, the solution of the system of linear equations is (1.33, 1).

5 0
2 years ago
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Jackie bought a 3-pack of tubes of glue. She used 0.27 ounce of the glue from the 3-pack
brilliants [131]

Answer:

0.54 ounces in each tube

Step-by-step explanation:

Add the amount she used so we can add it in. 1.35+0.27= 1.62. Then divide it by the number of tube and since it was a 3 pack you divide it by 3. 1.62/3=0.54 so there is 0.54 ounces in each tube.

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What number must we multiply by $-\frac23$ to get a product of $\frac34$?
stich3 [128]

Let x be unknown number. If number x is multiplied by -\dfrac{2}{3} and the product is equal to \dfrac{3}{4}, then

x\cdot \left(-\dfrac{2}{3}\right)=\dfrac{3}{4}.

To find x you should divide \dfrac{3}{4} by -\dfrac{2}{3}:

x=\dfrac{\dfrac{3}{4}}{-\dfrac{2}{3}}=\dfrac{3}{4}\cdot \left(-\dfrac{3}{2}\right)=-\dfrac{3\cdot 3}{4\cdot 2}=-\dfrac{9}{8}.

Answer: x=-\dfrac{9}{8}

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2 years ago
A- 5.57<br> B- 41<br> C-12<br> D-21.71
Kryger [21]

Answer:

Step-by-step explanation:

If KM bisects angle NKL, the angle 3 is congruent to angle 4.  

We are given that angle 1 is congruent to angle 2, so that means that angle JKP is congruent to angle PKN.  By the definition of an angle bisector, we know then that angle NKM is congruent to angle MKL.  By the definition of a straight angle formed by opposite rays, all those angles named above add up to equal 180 degrees.  So if angle JKN = 8x + 2 and angle MKL = 3x + 5 and angles NKM and MKL are congruent, then angle NKL = 2(3x + 5) which is 6x + 10.  Again, if all those angles above add up to equal 180, then

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Angle MKN = 41 degrees

4 0
2 years ago
Suppose the supply function for product x is given by qxs = - 30 + 2px - 4pz.
Igoryamba

It is given in the question that

Suppose the supply function for product x is given by

qxs = - 30 + 2px - 4pz.

And we have to find how much of product x is produced when px = $600 and pz = $60.

And for that, we have to substitute 600 for px and 60 for pz, and on doing so, we will get

qxs = -30+2(600)-4(60)&#10;\\&#10;qxs = -30 +1200 -240 = 930

And that's the required answer .

3 0
2 years ago
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