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LUCKY_DIMON [66]
2 years ago
5

Which table shows a function that is decreasing only over the interval (–1, 1)? A 2-column table with 5 rows. The first column i

s labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries 0, 3, 0, negative 3, 0. A 2-column table with 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries 10, 8, 0, negative 8, negative 10. A 2-column table with 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries 0, negative 3, 0, 3, 0. A 2-column table with 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 10, negative 8, 0, 8, 10.
Mathematics
2 answers:
aleksandrvk [35]2 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

I just took the test and got it right

Hopefully this helps you :)

pls mark brainlest ;)

slega [8]2 years ago
3 0

Answer:

its A.

Step-by-step explanation:

i just took the test

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A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marin
djyliett [7]

Answer:

A)  (7.6, 8.8)

which are the coordinates of the treasure.

Missing Problem Statement:

Given Options:

A) (11.4, 14.2)

B) (7.6, 8.8)

C) (5.7, 7.5)

D) (10.2, 12.6)

I have added the picture showing the traced map onto a coordinate plane to find exact location of treasure.

The coordinates of Tree are (16,21)

Coordinates of rock are (3,2)

Step-by-step explanation:

Let,

Coordinates of treasure be (a,b)

d_{1}= distance from tree to treasure

d_{2}=distance from rock to treasure

d_{1}=\sqrt{(16-x)^2 + (21-y)^2}

d_{2}=\sqrt{x\2 + (y-2)^2}

Given ratio between rock and tree, \frac{d_{2}}{ d_{1}}=\frac{5}{9}= 0.55_______(Equation.1)

which will be used to locate the treasure.

Now we just need to cross check by putting the coordinates given in the options one by one to find out value of d_{1},d_{2} and checking if it satisfies the Equation 1.

Check (A) (11.4, 14.2)

d_{2}= 14.8, d_{1}= 8.2,

\frac{d_{2}}{ d_{1}}= 1.8

Check (C) (5.7, 7.5)

d_{2}= 6.13, d_{1}= 16.98,

\frac{d_{2}}{ d_{1}}= 0.36

Check (D) (10.2, 12.6)

d_{2}= 12.8, d_{1}= 10.2,

\frac{d_{2}}{ d_{1}}= 1.25

Check (B) (7.6, 8.8)

d_{2}= 8.2, d_{1}= 14.8,

\frac{d_{2}}{ d_{1}}= 0.55

Which satisfies Equation 1, such that ratio between rock and tree is 5:9 or  \frac{d_{2}}{ d_{1}}=\frac{5}{9}= 0.55

So, the coordinates of the treasure are (B) (7.6, 8.8)

7 0
2 years ago
Read 2 more answers
The lengths of the sides of a rectangular window have the ratio 1.2 to 1. The area of the window is 1920 square inches. What are
PilotLPTM [1.2K]
The answer is 40 by 48 inches

40 * 48 = 1920
5 0
2 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
1 year ago
Jessica deposits $5,000 at the end of each year in an account earning 2.45% interest, compounded annually. What is the future va
denpristay [2]
Hi there
If the amount deposited at (end) of each year, use the formula of the (future/present) value of annuity ordinary

If the amount deposited at the (beginning) of each year use the formula of the (future/present) value of annuity due

So
FvAo=5,000×(((1+0.0245)^(5)−1)
÷(0.0245))
=26,255.38...answer

Hope it helps

8 0
2 years ago
A craft vendor must sell at least $300 worth of merchandise to make a profit. Scarves sell for $10 each and hats sell for $20 ea
valina [46]
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.

Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit. 

Let s represent scarves and h represent hats.

10s + 20h <u>></u> 300
s + h <u>></u> 20

We use inequality because the problem states "at least". 

s + h = 20
10s + 20h = 300

s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10

s = 20 - h
s = 20 - 10
s = 10

s + h <u>></u> 20
10 + 10 <u>></u> 20

10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300

7 0
2 years ago
Read 2 more answers
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