Answer:
Equal df
Step-by-step explanation:
Given that a chi square test for goodness of fit is used to examine the distribution of individuals across three categories,
Hence degree of freedom = 3-1 =2
Similarly for a chi-square test for independence is used to examine the distribution of individuals in a 2×3 matrix of categories.
Here degree of freedom = (r-1)(c-1) where r = no of rows and c =no of columns
= (2-1)(3-1) = 2
Thus we find both have equal degrees of freedom.
<span>At least 75% of the data will fall within 2 standard deviations of the mean.
This is tricky problem. Usually when you're dealing with standard deviation, you have a bell curve, or something close to a bell curve and for such a data distribution, there will be approximately 95% of the data within 2 standard deviations of the mean. But if you don't know that you have a bell curve, you have to fall back to Chebyshev’s Theorem, which states that at least 75% of the data points will fall within 2 standard deviations of the mean for any set of numbers.</span>
Answer:
2h x (l+b)
2x10 X (12+10)
20 X 22
44 cm cube is your answer...
The gardener will need to buy 60 feet of fencing. Because the square root of 225 if 15, and 15 times 4 is 60. So, 60 is the perimeter of the garden.
