On her first stroke, Maria hit a golf ball 140 yards 2 feet 9 inches. On her second stroke, she hit it 170 yards 1 foot 6 inches
2 answers:
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Answer:
a. b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349
Step-by-step explanation:
a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.
b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.
c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842
d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166
e. The z-score related to 6.4 kg is and the z-score related to 7 kg is
, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194
f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349
This is annoying
the perimiter is 34 units
the width is 6.5 units
ok.
perimiter=2(Length+Width)
P=2(L+W)
solve for L
distribute
P=2L+2W
minus 2W
P-2W=2L
divide by 2
given that P=34 units and W=6.5 units
the equation would be
or 
the perimiter is 34 units
the width is 6.5 units
ok.
perimiter=2(Length+Width)
P=2(L+W)
solve for L
distribute
P=2L+2W
minus 2W
P-2W=2L
divide by 2
given that P=34 units and W=6.5 units
the equation would be