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Brums [2.3K]
2 years ago
10

A young woman wants to make at least $200 a week and can't work no more than 30 hours a week. she works at the library for $8 an

hour and babysits for $6 an hour.
a. What system of inequalities shows the possible combination of hours and jobs she can work?
b. Why did you exclude points to the left of the y-axis and below the x-axis
Mathematics
1 answer:
Bas_tet [7]2 years ago
5 0
Let, Number of Hours in Library = x
Number of Hours in babysitting = y

Inequality would be: x + y = 30  ;
 &   8x + 6y ≥ 200

b) Solving: Multiply first equation by 6, 
6x + 6y ≥ 180
Subtract it from 2nd equation, 
2x ≥ 20
x ≥ 10

Now, substitute it in 1st equation, 
10 + y = 30
y = 20

Your Answer would be (10, 20)
x - value is lesser or equal to 10, so it would move to left (decreasing direction)!

Hope this helps!
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Point G is on segment FH such that it partitions segment FH into a ratio of 2:3.Point F is located at (5, 7) and point H is loca
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Answer:

G = (9.4, 9,4)

Step-by-step explanation:

The ratio is applied in the x-distance and the y-distance. The ratio is 2:3 so you have to divide the distances by 5 and 2/5 correspond to FG and 3/5 to GH

x-distance:

x2 - x1 = 16 - 5 = 11

11/5 = 2.2

y-distance:

y2 - y1 = 13 - 7 = 6

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Point G = (5, 7) + (4.4, 2.4)

= (9.4, 9.4)

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2 years ago
A manager states that his process is really working well. Out of 1,500 parts, 1,477 were produced free of a particular defect an
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Answer:

The answer is explained below

Step-by-step explanation:

STEP 1

Out of 1500 units produced by a company 1,477 are found to be free of a particular type of defect. One needs to rate the performance based on Six Sigma Theory.

STEP 2

Manager can define the performance of a product using defects per million units DPMO metric

DPMO can be find by using

DPMO = Total number of defects in a sample/ No. of opportunities of per error per unit x No. of units * 1,000,000

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          = 23/1500

          = 15,333,33

The defect rate of the process can be find by

Defect rate = No. of defects/ No. of units * 100

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Six Sigma theory focuses on achieving 3.4 defects per million for a certain period of time. However in this, performance of the process is not as good as stated by the manager.

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Darcie wants to crochet a minimum of 3 blankets. Darcie crochets at a rate of 1/15 of a blanket a day. She has 60 days until she
NNADVOKAT [17]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal can be given as:

s\leq 15

Step-by-step explanation:

The complete question is:

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

Given:

Darcie wants to crochet a minimum of 3 blankets to donate.

Rate at which she crochet = \frac{1}{15} of a blanket per day.

Maximum number of days she has = 60.

To find the number of days Dancie can skip out of 60 days and still reach her goal.

Let s represent the number of days she can skip.

Number of days left to crochet = (60-s) days

At rate of  \frac{1}{15} of a blanket per day, number of blankets Dancie can corchet in (60-s) days can be given as :

⇒ \frac{1}{15}(60-s)

Simplifying using distribution.

⇒ (\frac{1}{15}.60)-(\frac{1}{15}.s)

⇒ 4-\frac{s}{15}

Dancie needs to crochet a minimum of 3 blankets to reach her goal.

Thus, the inequality can be given as:

4-\frac{s}{15}\geq 3

Solving the inequality for s

Subtracting 4 both sides.

4-4-\frac{s}{15}\geq 3-4

-\frac{s}{15}\geq -1

Multiplying both sides by -15.

-15(-\frac{s}{15})\leq -15(-1) [On multiplying by a negative number the sign of inequality reverse]

∴ s\leq 15

Thus, Dancie can skip a maximum of 15 days.

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