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Brums [2.3K]
2 years ago
10

A young woman wants to make at least $200 a week and can't work no more than 30 hours a week. she works at the library for $8 an

hour and babysits for $6 an hour.
a. What system of inequalities shows the possible combination of hours and jobs she can work?
b. Why did you exclude points to the left of the y-axis and below the x-axis
Mathematics
1 answer:
Bas_tet [7]2 years ago
5 0
Let, Number of Hours in Library = x
Number of Hours in babysitting = y

Inequality would be: x + y = 30  ;
 &   8x + 6y ≥ 200

b) Solving: Multiply first equation by 6, 
6x + 6y ≥ 180
Subtract it from 2nd equation, 
2x ≥ 20
x ≥ 10

Now, substitute it in 1st equation, 
10 + y = 30
y = 20

Your Answer would be (10, 20)
x - value is lesser or equal to 10, so it would move to left (decreasing direction)!

Hope this helps!
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A line segment has endpoints at (–4, –6) and (–6, 4). Which reflection will produce an image with endpoints at (4, –6) and (6, 4
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Mason practiced basketball free throws and kept track of the results in the table. He says the experimental probability of makin
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6 0
1 year ago
Paul and jose are trying to measure the height of a tree. paul is standing 19m from the foot of the tree and measures the angle
Nina [5.8K]
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as x.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
cos(59)= \frac{19}{h}
h= \frac{19}{cos(59)}
h=36.9
Now we can use the law of sines to find the distance x between Paul and Jose:
\frac{sin(43)}{36.9} = \frac{sin(16)}{x}
x= \frac{36.9sin(16)}{sin(43)}
x=14.9

Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
19m+14.9=33.9m

We can conclude that Jose is 33.9m from the base of the tree.

3 0
2 years ago
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