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Brums [2.3K]
1 year ago
10

A young woman wants to make at least $200 a week and can't work no more than 30 hours a week. she works at the library for $8 an

hour and babysits for $6 an hour.
a. What system of inequalities shows the possible combination of hours and jobs she can work?
b. Why did you exclude points to the left of the y-axis and below the x-axis
Mathematics
1 answer:
Bas_tet [7]1 year ago
5 0
Let, Number of Hours in Library = x
Number of Hours in babysitting = y

Inequality would be: x + y = 30  ;
 &   8x + 6y ≥ 200

b) Solving: Multiply first equation by 6, 
6x + 6y ≥ 180
Subtract it from 2nd equation, 
2x ≥ 20
x ≥ 10

Now, substitute it in 1st equation, 
10 + y = 30
y = 20

Your Answer would be (10, 20)
x - value is lesser or equal to 10, so it would move to left (decreasing direction)!

Hope this helps!
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THat would be 6 units to the right and 3 units up.

B
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For a fundraiser, each donor package contains 333 food vouchers and 555 raffle tickets. Complete the double number line diagram
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It's A

Step-by-step explanation:

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Last one for now: Given m<AFB=25, m<BAF=105, and m<AGD=86, find mAC
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See attached picture for the answer:

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Quadrilateral ABCD is inscribed in circle P as shown. Which statement is necessarily true? A. `"m"/_A +"m"/_B = "m"/_C + "m"/_D
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Opposite angles of an inscribed quadrilateral are supplementary, so it is true that ...

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Determine whether the lines are parallel, intersect, or coincide. x-5y=0, y+1=1/5(x+5)
MAXImum [283]

<u>Answer-</u>

<em>The lines are two </em><em>coinciding lines</em><em> or the </em><em>same lines</em><em>.</em>

<u>Solution-</u>

The given line equations are

the first one,

\Rightarrow x-5y=0  

the second one,

\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0

As we know two line equations A_1x+B_1y+C_1=0 and A_2x+B_2y+C_2=0 will be,

  1. Parallel if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}
  2. Coincide if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}
  3. Intersect if, \dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}

As here,

\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}

\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

4 0
2 years ago
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