Leslie started last week with $1200 in her checking account. During the week, she wrote the checks below. Trans typ./ Check no.
1 answer:
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Hello,
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.
Step-by-step explanation:
The given is,
Dimensions of square has length of 10 cm
Trapezoid has base lengths of 8 cm and 14 cm
The length of the trapezoid is 4 cm
Rectangle has side length of 20 cm and 6 cm
Step:1
Area of composite figure = Area of square + Area of Trapezoid
+ Area of rectangle.......................(1)
Step:2
Formula for area of square,
where, a - side of length = 10 cm
Area of square, = 100 Square centimeter
Step:3
Formula for area of Trapezoid,
=
.......................................(2)
Where, a - 8 cm
b - 14 cm
h - 4 cm
From equation (2)
=
=
= 44
Area of Trapezoid, = 44 square centimeters
Step:4
Formula for area of rectangle,
......................................(3)
Where, l = 20 cm
b = 6 cm
Equation (3) becomes,
= 120
Area of rectangle, = 120 square centimeters
Step:5
From Equation (1),
= 100 + 44 + 120
= 264 square centimeters
Result:
The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.