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Veseljchak [2.6K]

2 years ago

14

En las competencias de atletismo hay 120 participantes; 30 en la prueba de 100 m, 50 en la de 200 m y 40 en la carrera de relevo

s; pero también hay 10 que participan en las 3 pruebas. ¿Cuál es la probabilidad de que un participante esté inscrito solamente en una prueba?

1 answer:

IceJOKER [234]2 years ago

7 0

Answer:

120 by the questiom we have tl do plus or not

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Tan 235° = 2tan20°+ tan215°

Mariulka [41]

Given : tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20 = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20 = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20 = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20 = (Tan 55 - Tan 35) /2

=> 2 Tan 20 = Tan 55 - Tan 35

=> 2 Tan 20 + Tan 35 = Tan 55

=> tan 55 = 2tan 20 + tan 35

=> tan 235 = 2tan 20 + tan 215

QED

Hence Proved

5 0

2 years ago

What are the explicit equation and domain for an arithmetic sequence with a first term of 8 and a second term of 5? 20 pts.

fgiga [73]

ANSWER

$a_n = 11 - 3n$

EXPLANATION

The explicit rule for an arithmetic sequence is given by:

$a_n = a_1 + d(n - 1)$

It was given that:

$a_1 = 8$

and

$a_2 = 3$

The common difference is

$d = 5 - 8 = - 3$

We plug in the values into the explicit formula to get,

$a_n = 8+ - 3(n - 1)$

Expand to get,

$a_n = 8 - 3n + 3$

The explicit rule is

$a_n = 11 - 3n$

6 0

2 years ago

Find all x in set of real numbers R Superscript 4 that are mapped into the zero vector by the transformation Bold x maps to Uppe

sukhopar [10]

Answer:

$x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right]$

Step-by-step explanation:

According to the given situation, The computation of all x in a set of a real number is shown below:

First we have to determine the $\bar x$ so that $A \bar x = 0$

$\left[\begin{array}{cccc}1&-3&5&-5\\0&1&-3&5\\2&-4&4&-4\end{array}\right]$

Now the augmented matrix is

$\left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\2&-4&4&-4\ |\ 0\end{array}\right]$

After this, we decrease this to reduce the formation of the row echelon

$R_3 = R_3 -2R_1 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&2&-6&6\ |\ 0\end{array}\right]$

$R_3 = R_3 -2R_2 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right]$

$R_2 = 4R_2 +5R_3 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&4&-12&0\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right]$

$R_2 = \frac{R_2}{4}, R_3 = \frac{R_3}{-4} \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&1\ |\ 0\end{array}\right]$

$R_1 = R_1 +3 R_2 \rightarrow \left[\begin{array}{cccc}1&0&-4&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right]$

$R_1 = R_1 +5 R_3 \rightarrow \left[\begin{array}{cccc}1&0&-4&0\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right]$

$= x_1 - 4x_3 = 0\\\\x_1 = 4x_3\\\\x_2 - 3x_3 = 0\\\\ x_2 = 3x_3\\\\x_4 = 0$

$x = \left[\begin{array}{c}4x_3&3x_3&x_3\\0\end{array}\right] \\\\ x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right]$

By applying the above matrix, we can easily reach an answer

5 0

2 years ago

Find the common ratio of the sequence. 3, 9, 27, 81,...<br> •3 <br> •6<br> •1/3<br> •-6

Mila [183]

Answer:

Common ratio: 3

Step-by-step explanation:

well 3 to 9 is multiplying by 3

9 to 27 is by multipling by 3

27 to 81 is by multipling by 3

6 0

2 years ago

Read 2 more answers

Find the area of equilateral triangle with side a.

marishachu [46]

Answer:

$\frac{\sqrt{3} }{4} a^2$

Step-by-step explanation:

To find the area of an equilateral triangle, we can apply a formula.

$A=\frac{\sqrt{3} }{4} s^2$

$A= area\\s=side \: length$

The side length is given a.

Plug a in the formula as the side length.

$A=\frac{\sqrt{3} }{4} a^2$

8 0

2 years ago