Answer:
F(n) = 225 +(n)300
Step-by-step explanation:
It is given that the fish counts of last 3 weeks are as follows,
<em>225, 525 and 825.</em>
The difference between consecutive terms is 300.
<em>If we carefully look, these are numbers in arithmetic progression, with first term as 225 and common difference as 300.</em>
Thus, at the end of nth week, with initial amount of fish at n=0 as 225, the fish count is given by,
F(n) = 225 +(n)300, where F(n) in function of total number of fishes and n is the number of weeks.
We can verify as, at<em> n=1, F(1) = 225 + 300 = 525 and F(2) = 225 + 600 = 825, </em>which are already correctly given.