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Sergeu [11.5K]
2 years ago
13

HURRY! Which table represents a linear function?

Mathematics
1 answer:
jeka942 years ago
7 0
Remember that to tell if a function is linear for a table, you should look for a constant rate of change, and the only function that has a constant rate of change is the first one. x is increasing by 1, and y is increasing by 0.5.

Now that we know that, lets find the equation of our table.
First, lets take tow points from our table: (1,\frac{1}{2}) and (2,1).
Next, use the slope formula: m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } 
We know for our points that y_{2}=1, y_{1}= \frac{1}{2},x_{2}=2, and x_{1}=1, so lets replace those point in our formula to find m:
m= \frac{1- \frac{1}{2} }{2-1}
m= \frac{1}{2}

Finally, we can use the point slope formula y-y_{1}=m(x-x_{1}) to find our equation:
y- \frac{1}{2} = \frac{1}{2} (x-1)
y- \frac{1}{2} = \frac{1}{2} x- \frac{1}{2}
y= \frac{1}{2}x

We can conclude that the first table represents a linear function, and its equation is y= \frac{1}{2}x  
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The weekly salary paid to employees of a small company that supplies​ part-time laborers averages ​$750 with a standard deviatio
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Answer:

(a) The fraction of employees is 0.84.

(b)

\mu=850\\\\\sigma=450

(c)

\mu=787.5\\\\\sigma=472.5

(d) No. The left part of the distribution would be truncated too much.

Step-by-step explanation:

(a) If the weekly salaries are normally​ distributed, estimate the fraction of employees that make more than ​$300 per week.

We have to calculate the z-value and compute the probability

z=\frac{X-\mu}{\sigma}= \frac{300-750}{450}=\frac{-450}{450}=-1\\\\P(X>300)=P(z>-1)=0.84

(b) If every employee receives a​ year-end bonus that adds ​$100 to the paycheck in the final​ week, how does this change the normal model for that​ week?

The mean of the salaries grows $100.

\mu_{new}=E(x+C)=E(x)+E(C)=\mu+C=750+100=850

The standard deviation stays the same ($450)

\sigma_{new}=\sqrt{\frac{1}{N} \sum{[(x+C)-(\mu+C)]^2}  } =\sqrt{\frac{1}{N} \sum{(x+C-\mu-C)^2}  }\\\\ \sigma_{new}=\sqrt{\frac{1}{N} \sum{(x-\mu)^2}  } =\sigma

(c) If every employee receives a 5​% salary increase for the next​ year, how does the normal model​ change?

The increases means a salary X is multiplied by 1.05 (1.05X)

The mean of the salaries grows 5%, to $787.5.

\mu_{new}=E(ax)=a*E(x)=a*\mu=1.05*750=487.5

The standard deviation increases by a 5% ($472.5)

\sigma_{new}=\sqrt{\frac{1}{N} \sum{[(ax)-(a\mu)]^2}  } =\sqrt{\frac{1}{N} \sum{a^2(x-\mu)^2}  }\\\\ \sigma_{new}=\sqrt{a^2}\sqrt{\frac{1}{N} \sum{(x-\mu)^2}}=a*\sigma=1.05*450=472.5

(d) If the lowest salary is ​$300 and the median salary is ​$525​, does a normal model appear​ appropriate?

No. The left part of the distribution would be truncated too much.

7 0
2 years ago
Eighteen 2.5 gallon buckets are needed to fill a cistern with water. Find the constant of variation. Please help! Thank you!
Allushta [10]

Given:

Eighteen 2.5 gallon buckets are needed to fill a cistern with water.

To find:

The constant of variation.

Solution:

If y is directly proportional to x, then

y\propto x

y=kx

Where, k is constant of variation.

In the given problem, water in cistern (w) is directly proportional to number of buckets (n).

w\propto n

w=2.5n        (Capacity of each bucket is 2.5 gallons)

Therefore, the constant of variation is 2.5.

6 0
2 years ago
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What is the angle above the x axis (i.e., "north of east") for a vector with components (15 m, 8 m)?
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Answer:28.071

Step-by-step explanation:

Given

vector component is (15,8)

i.e. its x component is 15 from origin and y component is 8 m

So angle made by vector with x axis is

tan\theta =\frac{8}{15}

\theta =tan^{-1}\frac{8}{15}

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Which expression is equivalent to logw((x^2-6)^4/(cube root x^2+8))
Arturiano [62]

Answer: The expression is in the explanation.

Step-by-step explanation:

Please find the attached file for the solution.

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The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.1 in/s. At
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Given:

\dfrac{dr}{dt}=1.4\text{ in/s}

\dfrac{dh}{dt}=-2.1\text{ in/s}

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Solution:

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Differentiate with respect to t.

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Substitute the given values.

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\dfrac{dV}{dt}=\dfrac{22}{21}\times \left[-30240+58800\right]

\dfrac{dV}{dt}=\dfrac{22}{21}\times 28560

\dfrac{dV}{dt}=29920

Therefore, the volume of decreased by 29920 cubic inches per second.

6 0
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