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pochemuha
2 years ago
10

Se the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x2

yi + xy2j + 5xyzk, s is the surface of the tetrahedron bounded by the planes x = 0, y = 0, z = 0, and x + 4y + z = 4. 1104 125​ incorrect: your answer is incorrect.
Mathematics
1 answer:
zalisa [80]2 years ago
7 0

f(x,y,z)=x^2y\,\vec\imath+xy^2\,\vec\jmath+5xyz\,\vec k

\implies\nabla\cdot f=2xy+2xy+5xy=9xy

The plane has intercepts in the x,y plane at (4, 0, 0) and (0, 1, 0), so the flux is given by (via the divergence theorem)

\displaystyle\iint_Sf\cdot\mathrm dS=9\int_{x=0}^{x=4}\int_{y=0}^{y=1}\int_{z=0}^{z=4-x-4y}xy\,\mathrm dz\,\mathrm dy\,\mathrm dx=-48

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Matty’s piano book includes 15 songs in the key of C, 10 in the key of G, and 5 in the key of F. The songs from all three keys a
Marta_Voda [28]

Matty's piano is going to a random key of c next.

6 0
2 years ago
If $9x^2 - 16x + k$ is a perfect square trinomial, find $k$.
Lady_Fox [76]

Answer:is this a real quistion

Step-by-step explanation:?

7 0
2 years ago
• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
2 years ago
Rewrite the expression using Distributive Property, then simplify<br><br> -1(x-9)+4x
pentagon [3]
First ask yourselfhat needs to be dristributed.
That would be -1 (x-9)
To distribute you have to multiply the number out side of the parentheses (-1) by each term inside the parentheses( x and -9)
-1×x=-x
-1×-9=9
Now the expression is
-x+9+4x
To simplify you have to combine like terms (4x and-x)
4x-x=3x
Your answer is 9+3x or 3(3+x).
5 0
2 years ago
What is the area of the shaded region?
azamat

Answer:

(25\pi\ -24)\ cm^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the circle minus the area of the two isosceles triangles

so

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

where r is the radius of the circle

In this problem we have

r=5\ cm

substitute

A=\pi (5)^{2}

A1=25\pi\ cm^{2}

Find the area of the two triangles

The area of the two isosceles triangles is equal to

A=2[\frac{1}{2}bh]=bh

we have

b=6\ cm

h=5-1=4\ cm

substitute

A2=6*4=24\ cm^{2}

Find the area of the shaded region

A1-A2=(25\pi\ -24)\ cm^{2}

5 0
2 years ago
Read 2 more answers
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