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shutvik [7]
2 years ago
6

Implicit information requires the reader to combine details from the text with background knowledge to make a(n) . -guess -theor

y -inference -statement
Mathematics
2 answers:
Ronch [10]2 years ago
6 0

Answer:

The answer is C

Step-by-step explanation:

I don't have a full explanation, but when I took the test I got it right. If you want a step-by-step explanation, look at the other guys.

klio [65]2 years ago
3 0
The correct answer that would best complete the given statement above would be the third option: INFERENCE. <span>Implicit information requires the reader to combine details from the text with background knowledge to make an inference. An inference is a conclusion that is based on evidence or reasoning. </span>
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A student estimates the weight of astronauts on the moon by multiplying their weight by the decimal 0.16666....what fraction can
Elden [556K]

Let x = 1.66666... ....(1)

Multiply both sides of equation (1) by 10.

10x = 1.666666.... .... (2)

Multiply both sides of equation (1) by 100.

100x = 16.66666....... (3)

Subtract equation (2) from equation (3)

100x - 10x = 16.66666...- 1.66666...

90x = 15

x= \frac{15}{90}  = \frac{1}{6}

Hence, the required fraction form is \frac{1}{6} .... Answer.


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1 year ago
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categorize the graph as linear increasing, linear decreasing, exponential growth, or exponential decay.
soldier1979 [14.2K]
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1 year ago
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For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th
Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0
2 years ago
Please please please Factor 9x - 27xy
Kamila [148]

Common factor of 3x

3x ( 3x+9xy)( 1+0)

7 0
1 year ago
Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each
sp2606 [1]
Lets take Gregs weight as “x”. This means that Justins weight is x-15, and x/2 = (x-15)-75.

If we take that last equation, lets combine like terms:

x/2 = x - 15 - 75
x/2 = x - 90
Now multiply both sides by 2 to get rid of the fraction
x = 2x - 180
Subtract 2x from both sides
x - 2x = -180
-x = -180
x = 180 — this is Gregs weight

Justins weight is x-15, so 180-15, which is 165 pounds. Hope this helped.
5 0
1 year ago
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