Answer:
The answer should be A, let me know if that's wrong.
Step-by-step explanation:
Answer:
Yes, but it is not linear. It is exponential : 
Step-by-step explanation:
On the first day we have 5 bacteria.
On the second day we will have 5*2 = 10 bacteria.
On the third day we will have 10*2 = 5*2*2 = 5*2^2 = 20 bacteria.
On the fourth day we will have 20*2 = 5*2*2*2 = 5*2^3 = 40 bacteria.
We can see that
,
where x is a number of days and f(x) gives us the number of bacteria.
Answer: 0.5898
Step-by-step explanation:
Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .
We assume that,
The probability that .J. Redick makes any given free throw =0.901 (1)
Free throws are independent.
So it is a binomial distribution .
Using binomial probability formula, the probability of getting success in x trials :

, where n= total trials
p= probability of getting in each trial.
Let x be binomial variable that represents the number of a=makes.
n= 14
p= 0.901 (from (1))
The probability that he makes at least 13 of them will be :-

![=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898](https://tex.z-dn.net/?f=%3D%5E%7B14%7DC_%7B13%7D%280.901%29%5E%7B13%7D%281-0.901%29%5E1%2B%5E%7B14%7DC_%7B14%7D%280.901%29%5E%7B14%7D%281-0.901%29%5E0%5C%5C%5C%5C%3D%2814%29%280.901%29%5E%7B13%7D%280.099%29%2B%281%29%280.901%29%5E%7B14%7D%5C%20%5C%20%5B%5Cbecause%5C%20%5EnC_n%3D1%5C%20%5C%26%5C%20%5EnC_%7Bn-1%7D%3Dn%20%5D%5C%5C%5C%5C%5Capprox0.3574%2B0.2324%3D0.5898)
∴ The required probability = 0.5898
Let's analyse the function

The amplitude is A, so we want A=1.5
Now, we start at x=0, and we have 
After one second, i.e. x=1, we want this sine function to make 330 cycles, i.e. the argument must be 
So, we have

so, the function is

Answer:
½log3 + ½logx
Step-by-step explanation:
½(log(3x))
½(log3 + logx)
½logx + ½log3