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Anvisha [2.4K]
2 years ago
10

Here are Babe Ruth's home run totals for the New York Yankees during the years 1920 - 1934:54, 59, 35, 41, 46, 25, 47, 60, 54, 4

6, 49, 46, 41, 34, 22Which of the following is a box-and-whisker plot for this data set?

Mathematics
2 answers:
Irina-Kira [14]2 years ago
5 0

Given data is 54, 59, 35, 41, 46, 25, 47, 60, 54, 46, 49, 46, 41, 34, 22

Arranging it in increasing order:

22 25 34 35 41 41 46 46 46 47 49 54 54 59 60

Number of data items, n=15.

Finding Median, First Quartile, and Third Quartile

Finding\;\;median\\M=\frac{n+1}{2}th\;\;term =\frac{15+1}{2}=8th\;\;term\;\; i.e. \;\;46

22 25 34 35 41 41 46 46 46 47 49 54 54 59 60

Now finding First Quartile from set: 22 25 34 35 41 41 46

Q₁ = middle term i.e. 35

Now finding Third Quartile from set: 46 47 49 54 54 59 60

Q₃ = middle term i.e. 54

So we have Q₁ = 35, M = 46, and Q₃ = 54. Lower bound is 22 and Upper bound is 60.

While drawing the given data on number line and marking First quartile, Median, Third quartile on number line. We can clearly observe that option A matches with given data points.

Hence, option A i.e. Box-plot A is the correct choice.

valina [46]2 years ago
5 0

Answer:

he's right, the answer is A. thank you once again

Step-by-step explanation:

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Answer:

Here is the question attached with.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF is a straight line.

\angle AEF is a right angled triangle.

Options 1,4,5,6 are correct answers.

Step-by-step explanation:

⇒As \ ray\ AE  is ⊥FEC so it will forms right angled triangle then m\angle CEA =90\ (deg).

⇒Measure of \angle BEF =135\ (deg) as \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB is the bisector of \angle AEC,meaning that  \angle AEB is half of \angle AEC so  \angle AEB = 45\ (deg).

⇒\angle CEF is a straight line as the angles measure over it is 180\ (deg).

⇒Measure of \angle AEF = 90\ (deg) from linear pair concept.

As \angle CEA + \angle AEF = 180\ (deg),plugging the values of  m\angle CEA =90\ (deg) we have \angle AEF = 90\ (deg) .

The other two options are false as:

  • m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225

       it is exceeding 180\ (deg) whereas \angle CEF is a              

      straight line.

  • And m\angle CEB=2(m\angle CEA) is not true.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

So we have total 4 answers.

The correct options are 1,4,5,6.

5 0
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Answer:

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Step-by-step explanation:

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(0,346)(2,344.8)
slope = (344.8 - 346) / (2 - 0) = -1.2 / 2 = -0.6

y = mx + b
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now we sub and find b, the y int
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so ur equation is : y = -0.6x + 346

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I hope that's the answer.

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