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34kurt
2 years ago
8

Greg makes a pan of brownies. He takes 2/3 of the brownies to his friends house. He freezes 1/4 of the brownies. He gives the re

maining brownies to his 4 sisters. His sisters equal share the remaining brownies. what fraction of the pan of brownies does each sister get?
Mathematics
2 answers:
Cerrena [4.2K]2 years ago
4 0
2/3 + 1/4 = 11/12
11/12 divided by 4
0.229166667
So each sister gets <span><span>0.229 </span>of</span> the remaining brownies.
arsen [322]2 years ago
3 0
One over sixteen. you add up all the fractions to get 11 over 12 then divide 1 over 12 by 4 to get one over sixteen hope this helps
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What is the zero in the quadratic function f(x)= 9x^2-54x-19?
Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is


x=\frac{-b+\sqrt{b^2-4ac} }{2a}.


It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions.  Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}

We will now solve for the plus and the minus.

The plus,,,

x=\frac{54+\sqrt{3600}}{18}\\x=\frac{54+60}{18}\\x=\frac{114}{18}\\x=6.3

and the minus...

x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...

8 0
2 years ago
Trapezoid EFGH has coordinates E(−3, 4) , F(1, 4), G(3, 1) , and H(−5, 1) . Trapezoid E'F'G'H' has coordinates E′(−12, 16) , F′(
julia-pushkina [17]
I believe that the answer would be C
8 0
1 year ago
Read 2 more answers
Maddy is carrying a 555 liter jug of sports drink that weighs 7.5\text{ kg}7.5 kg7, point, 5, start text, space, k, g, end text.
Lelu [443]

Answer:

w/2 = 7.5/5

3kg

Step-by-step explanation:

Remaining question below:

Which proportion could Maddy use to model this situation?

a. w/2 = 7.5/5

b. w/7.5 = 5/2

Solve the proportion to determine the weight of a 2 liter jug.

_____kg

5 liters jug of sport drink weighs 7.5kg

2 liters jug of sport drink will weigh x kg

Find w

Ratio of weight to volume

7.5kg : 5liters=7.5/5

wkg : 2 liters=w/2

Equates the ratio

7.5 / 5 = w / 2

Cross product

7.5*2=5*w

15=5w

Divide both sides by 5

3=w

w=3kg

Therefore, weight of the 2liters jug of sport drink is 3kg

6 0
1 year ago
Read 2 more answers
wes has six errands to run (picking up the dry cleaning, going to the grocery store, getting gas, going to the bank, going to th
ss7ja [257]
If you did 1*2*3*4*5*6 it's 720
4 0
1 year ago
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According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating
Natali [406]

Answer:

a) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

H_0: \mu=32.48\\\\H_a:\mu< 32.48

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565

The degrees of freedom for this sample size are:

df=n-1=65-1=64

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

<u>Critical value approach</u>

<u></u>

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0
1 year ago
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