Please express those fractions properly: 3/4, 7/8.
Let g be the # of gallons the tank could hold when full.
Then (3/4)n + 5 = (7/8)n.
solving for n: Mult all 3 terms by the LCD (8): 6n + 5(8) = 7n.
Then n=5(8) = 40 (gallons). The tank would hold 40 gallons of water were it full.
Answer: "Use the straightedge to draw a line through points X and Y." is the right answer.
Step-by-step explanation:
To perpendicular bisector of line segment AB. There are following steps:
1) Draw arcs from points A and B on the both sides of AB.
2) Name the intersection points as X and Y.
3) Use the straightedge to draw a line through points X and Y.
4) Name the point as O
hence we have construct perpendicular bisector XY of AB which bisects at O.
The percentage that the store has taken off would be 30%.
Answer:
Step-by-step explanation:
245000 last year
This year 25235
(y2 - y1) / y1)*100 = your percentage change
(where y1=start value and y2=end value)
(( £25.235 - £24.500) / £24.500) * 100 = 0 %
There ain't no percentage change as there needs to be a bigger difference between the two numbers plus u should use the formula
Answer:
26.11% of women in the United States will wear a size 6 or smaller
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

In the United States, a woman's shoe size of 6 fits feet that are 22.4 centimeters long. What percentage of women in the United States will wear a size 6 or smaller?
This is the pvalue of Z when X = 22.4. So



has a pvalue of 0.2611
26.11% of women in the United States will wear a size 6 or smaller