answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ainat [17]
2 years ago
13

What conclusions can be drawn about finding the quotient in scientific notation? Check all that apply. Start Fraction (9.6 times

10 Superscript negative 8 Baseline) Over (3.2 times 10 Superscript 4 Baseline) End Fraction A.The coefficient of the solution is 6.4, the difference of the original coefficients. B.The exponent of the solution is –12, the difference of the original exponents. C.The coefficient of the solution must be greater than or equal to one but less than 10. D.The quotient is 3.0 × 10-12 E.The solution is a very large number.
Mathematics
2 answers:
bija089 [108]2 years ago
7 0

Answer:

B.The exponent of the solution is –12, the difference of the original exponents.

C.The coefficient of the solution must be greater than or equal to one but less than 10.

D.The quotient is 3.0 × 10^{-12}

Step-by-step explanation:

We are finding the quotient of the expression below in scientific notation

\dfrac{9.6X10^{-8}}{3.2X10^4} \\=\dfrac{9.6}{3.2}X10^{-8-4}\\ =3 X 10^{-12}

The following conclusions can be drawn

B.The power of 10 in the solution is –12, the difference of the original exponents.

C.The coefficient is 3, which is greater than or equal to one but less than 10.

D.The quotient is 3.0 × 10^{-12}

NemiM [27]2 years ago
4 0
<h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2 /><h2>What conclusions can be drawn about finding the quotient in scientific notation? Check all that apply. Start Fraction (9.6 times 10 Superscript negative 8 Baseline) Over (3.2 times 10 Superscript 4 Baseline) End Fraction A.The coefficient of the solution is 6.4, the difference of the original coefficients. B.The exponent of the solution is –12, the difference of the original exponents. C.The coefficient of the solution must be greater than or equal to one but less than 10. D.The quotient is 3.0 × 10-12 E.The solution is a very large number.</h2>
You might be interested in
Which statements are true? Check all that apply.
mariarad [96]

Answer:

A, B, and C

Step-by-step explanation:

A) We can see if this is a horizontal line if its slope is 0. Slope is change in y divided by change in x, so: slope = \frac{7-7}{3-(-2)} =\frac{0}{5} =0 . Thus, this is a horizontal line and the statement is correct.

B) Any equation of the form x = k, where k is a constant, will always be a straight line. Let's see if it goes through (-8, 3) by plugging in the values of -8 in for x and 3 in for y in the equation.

Clearly, we don't have a y, so we just put in the -8 for the x: -8 = -8. Since this is a true statement, we know that x = -8 does go through (-8, 3). So, this is a true statement.

C) We can see if this is a vertical line if its slope is undefined (for example, if the denominator is 0, it's undefined). Slope = \frac{5-(-7)}{0-0} =\frac{12}{0} = undefined. So, this is a vertical line and the statement is true.

D) As a basic fact, any point on a horizontal line will have the same y coordinate. However, their x coordinates may vary. Thus, the statement is false.

So, the answers are A, B, and C.

Hope this helps!

4 0
2 years ago
Read 2 more answers
The function f(x) = x2 has been translated 9 units up and 4 units to the right to form the function g(x). Which represents g(x)?
Alenkinab [10]

For this case, the parent function is given by:

f (x) = x ^ 2

We apply the following transformations:


Vertical translations:

Suppose that k> 0

To graph y = f (x) + k, move the graph of k units upwards:

For k = 9 we have:

h (x) = x ^ 2 + 9


Horizontal translations:

Suppose that h> 0

To graph y = f (x-h), move the graph of h units to the right

For h = 4 we have:

g (x) = (x-4) ^ 2 + 9

Answer:

The function g (x) is given by:

g (x) = (x-4) ^ 2 + 9

7 0
2 years ago
Read 2 more answers
Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random
lesya692 [45]
Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes P_B(A).

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
P(A|B)= \frac{P(A \cap B)}{P(B)}

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is \frac{1}{3}

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}

</span><span>P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

</span><span>Thus P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}

Therefore, P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}


Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
</span><span>
P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}

</span><span>P(D)= \frac{1}{3}</span><span>

Therefore, P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}</span>
3 0
2 years ago
Have you ever been swimming in a pool, and your eyes were red when you get out? This means the chemicals in the pool were not ad
soldier1979 [14.2K]

pH = f(x) = -log₁₀x

1. Graphs

I used Excel to calculate the pH values and draw the graphs (see the Figure).

f(x) and f(x) +1 are plotted against the left-hand axis, while f(x+ 1) is plotted against the expanded right-hand axis.

The points at which pH = 0 and pH = 1 are indicated by the large red dots.

2. x = 0.5

When x = 0.5, pH ≈0.30. The point is indicated by the red diamond.

3. Transformations

(a) ƒ(x) = -log(x) + 1

This function has no y-intercept, because log(0) is undefined.

(b) ƒ(x +1) = -log(x + 1)

f(0) = -log(0 + 1) = -log(1) = 0

This function has a y-intercept at (0,0).

hope this helps please mark me brainliest!

3 0
2 years ago
You and your mom enter a drawing with 3 different prizes. A total of 8 people entered the drawing, and prizes are awarded random
Rashid [163]
It's actually C. 6/336
8 0
2 years ago
Read 2 more answers
Other questions:
  • Suppose that 3 boys and 2 girls go to the theater and occupy 5 seats in a row. In how many ways can they be seated if all boys s
    14·2 answers
  • If a rectangle measures 15 inches by 1 3/4 feet, what is the perimeter in yards?
    6·1 answer
  • Lauren would like to find the midpoint of a line segment that has endpoints at (–0.5, 3) and (4, 7.5). Which statements are true
    14·2 answers
  • The formula for finding the interest on a loan is I = prt. Jack borrows $2,000 for 2 years at a rate of 2%. How much interest wi
    11·2 answers
  • John is planning to purchase a new car that costs $15,500. On average, a new car loses 11% of its value the moment that it is dr
    10·2 answers
  • Triangle RST was dilated by a scale factor of One-half. The image, triangle R'S'T', is an isosceles triangle, with each leg meas
    7·2 answers
  • Equation with parentheses help​
    13·1 answer
  • 8. For many computer tablets, the owner can set a 4-digit pass code to lock the device.
    8·1 answer
  • The perimeter of a pool table is about 7.8m. four times the length equals nine times the width. What are the dimensions of the t
    10·1 answer
  • NEED HELP ASAP!!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!