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2 years ago

11. In a certain town the ratio of the number of cars to that of taxis is 15:4. If

Mathematics

2 answers:

Snezhnost [94]2 years ago

7 0

Answer:

653 cars

Step-by-step explanation:

C : T

15:4

174/4 = 43.5

15 x 43.5 = 652.5

You cannot have 0.5 of a car so round up, therefore the answer is 653 cars.

Bess [88]2 years ago

4 0

Answer: 645 cars

Step-by-step explanation:

Divide 172 by 4 to find the multiple which is 43 so if 4 was multiplied by 43 to get 172 taxis you must multiply 15 by 43 which gives 645

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The Awnser Is C

Step-by-step explanation:

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1 year ago

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The New Haven High School cheerleaders got a t-shirt gun. The cheerleaders stand

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Answer: the gun was held 4ft high i.e H = 4ft

Step-by-step explanation:

To determine how high the gun was held when it was fired H;

Before firing the t-shirt up, the gun and the t-shirt are both at the same height.

Therefore,

H = h(0) i.e h(t) at t = 0

h(t) = -16t^2 + 64t + 4

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2 years ago

Linda works at the U-Pick Berry Farm selling strawberries and raspberries. Her first customer of the day bought 3 quarts of stra

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2 years ago

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A survey found that 73% of adults have a landline at their residence (event A); 83% have a cell phone (event B). It is known tha

4vir4ik [10]

Answer:

3. What is the probability that an adult selected at random has both a landline and a cell phone?

A. 0.58

4. Given an adult has a cell phone, what is the probability he does not have a landline?

C. 0.3012

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that an adult has a landline at his residence.

B is the probability that an adult has a cell phone.

C is the probability that a mean is neither of those.

We have that:

$A = a + (A \cap B)$

In which a is the probability that an adult has a landline but not a cell phone and $A \cap B$ is the probability that an adult has both of these things.

By the same logic, we have that:

$B = b + (A \cap B)$

The sum of all the subsets is 1:

$a + b + (A \cap B) + C = 1$

2% of adults have neither a cell phone nor a landline.

This means that $C = 0.02$ .

73% of adults have a landline at their residence (event A); 83% have a cell phone (event B)

So $A = 0.73, B = 0.83$ .

What is the probability that an adult selected at random has both a landline and a cell phone?

This is $A \cap B$ .

We have that $A = 0.73$ . So

$A = a + (A \cap B)$

$a = 0.73 - (A \cap B)$

By the same logic, we have that:

$b = 0.83 - (A \cap B)$ .

$a + b + (A \cap B) + C = 1$

$0.73 - (A \cap B) + 0.83 - (A \cap B) + (A \cap B) + 0.02 = 1$

$(A \cap B) = 0.75 + 0.83 - 1 = 0.58$

So the answer for question 3 is A.

4. Given an adult has a cell phone, what is the probability he does not have a landline?

83% of the adults have a cellphone.

We have that

$b = B - (A \cap B) = 0.83 - 0.58 = 0.25$

25% of those do not have a landline.

So $P = \frac{0.25}{0.83} = 0.3012$

The answer for question 4 is C.

4 0

1 year ago

It takes one machine 25 minutes to pick a bale of cotton and another machine 30 minutes to compete the same job. If both machine

gladu [14]

The first machine works at the rate x = 1 bale/ 25 min.
The second machine works at the rate y = 1 bale/30 min.

The combined rate is
x + y = 1/25 + 1/30 bales/min
= (30 + 25)/(25*30) = 55/750
= 11/150 bales/min

The time for both machines to pick 1 bale of cotton is
(1 bale)/(11/150 bales/min) = 150/11 min = 13.64 min

Answer: 13.6 minutes

6 0

2 years ago