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ikadub [295]
1 year ago
6

A square has an area that is less than 100 m2. What is a reasonable range for the graph of the square’s side?

Mathematics
2 answers:
damaskus [11]1 year ago
8 0
Square's side range is (√0,√100) =(0,10); this more than 0 and less than 10.
kozerog [31]1 year ago
6 0

Answer:

The range of the square's side is between 0 and 10 meters.

Step-by-step explanation:

The area of a square is defined as:

Area = x*x

Where <em>x</em> is the length of the square's side. It also could be writing as:

Area = x^{2}

Then, the question say that the area is less than 100 m^2, which means that the area have a value below 100 m^2. This is equivalent to write:

Area < 100m^{2}

x^{2} < 100m^{2}

Now we can solve for x and obtain:

x^{2} < 100m^{2}

x

x

Finally for getting a reasonable range for the square's side is logic to use a positive number and a number that also fulfill with this last condition (x<10m).

So, the range for the square's side is number greater than zero and smaller than 10 meters. It also could be writing as: (0,10)

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atroni [7]

Answer: a) 0.25, b) 0.78, c) 0.71

Step-by-step explanation:

Since we have given that

Number of employees in marketing = 4

Number of employees in management = 7

We need to hire committee of 3 people.

​a) Find the probability that the committee has exactly 2 employees from marketing.

So, Probability becomes

\dfrac{^4C_2\times ^7C_1}{^{11}C_3}\\\\=\dfrac{42}{165}\\\\=0.25

​b) Find the probability that the committee has at least one employee from marketing.

P(x\geq 1)=1-P(x=0)\\\\P(x\geq 1)=1-\dfrac{^7C_3}{^{11}C_3}=1-0.212=0.78

c) Find the probability that the committee has at most one employee from management.

P(x\leq 1)=P(x=0)+P(x=1)\\\\P(x\leq 1)=\dfrac{^7C_3}{^{11}C_3}+\dfrac{^7C_2\times ^4C_1}{^{11}C_3}\\\\P(x\leq 1)=0.21+0.50=0.71

Hence, a) 0.25, b) 0.78, c) 0.71

8 0
1 year ago
This​ year, druehl,​ inc., will produce 57 comma 60057,600 hot water heaters at its plant in​ delaware, in order to meet expecte
ivolga24 [154]
If one labour works 200 hours per month, the amount of hot water heaters the labour can produce is = 200 × 0.25 = 50 hot water heaters

The demand is to produce 57600 hot water heaters

The number of labourers employed is 57600 ÷ 50 = 1152 labourers
5 0
2 years ago
PLEASE HELP ME  Which of the following is the correct graph of the compound inequality 4p + 1 &gt; −7 or 6p + 3 &lt; 33? (1 poin
nikitadnepr [17]
The first inequality has solution
  4p > -8 . . . . . . subtract 1
  p > -2 . . . . . . . divide by 4
This is graphed as an open dot at -2, with shading to the right.

Neither inequality symbol includes "or equal to", so both dots are open dots. The appropriate choice is the first one:
  a number line with open circles at negative 2 and 5 with shading in between
4 0
2 years ago
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The intersection of planes AMR and CMR is<br> a. MR<br> b. AC<br> c. AR<br> d. none of the above
Maurinko [17]
I believe its either a or d

3 0
2 years ago
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The box office took in a total of $2905 in paid admissions for the high-school musical. Adult tickets cost $8 each, and student
Svet_ta [14]
There are no equations to choose from but it should look like the following.

a= # of adult tickets
s= # of student tickets

QUANTITY EQUATION
a + s= 560

COST EQUATION
$8a + $3s= $2905

***If you have to also solve for the number of adults and students, here are the steps.

STEP 1:
multiply quantity equation by -8

-8(a + s)= -8(560)
-8a - 8s= -4480

STEP 2:
add cost equation and step 1 equation

$8a + $3s= $2905
-8a - 8s= -4480
a term cancels out to zero
-5s= -1575
divide both sides by -5
s= 315 students

STEP 3:
substitute s=315 in quantity equation
a + s= 560
a + 315= 560
subtract 315 from both sides
a= 245 adults

ANSWER:
Quantity Equation
a + s= 560

Cost Equation
$8a + $3s= $2905

Hope this helps! :)
7 0
2 years ago
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