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ikadub [295]
2 years ago
6

A square has an area that is less than 100 m2. What is a reasonable range for the graph of the square’s side?

Mathematics
2 answers:
damaskus [11]2 years ago
8 0
Square's side range is (√0,√100) =(0,10); this more than 0 and less than 10.
kozerog [31]2 years ago
6 0

Answer:

The range of the square's side is between 0 and 10 meters.

Step-by-step explanation:

The area of a square is defined as:

Area = x*x

Where <em>x</em> is the length of the square's side. It also could be writing as:

Area = x^{2}

Then, the question say that the area is less than 100 m^2, which means that the area have a value below 100 m^2. This is equivalent to write:

Area < 100m^{2}

x^{2} < 100m^{2}

Now we can solve for x and obtain:

x^{2} < 100m^{2}

x

x

Finally for getting a reasonable range for the square's side is logic to use a positive number and a number that also fulfill with this last condition (x<10m).

So, the range for the square's side is number greater than zero and smaller than 10 meters. It also could be writing as: (0,10)

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Step-by-step explanation:

15 and 3

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2 years ago
if the current batch of pills is the first of the day and your goal is to produce a total of 600 what percentage of your goal wi
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Answer:

<u>12.5% ≈ 13%</u>

Step-by-step explanation:

The rest of the question is: There are 75 pills in the batch.

The current batch of pills is the first of the day and our goal is to produce a total of 600.

If there are 75 pills in the batch so percentage of goal completed will be

[(number of pills in the batch)/(Total pills)] * 100

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≈ 13% to the nearest whole number

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1 year ago
Prove the diagonals of the square with vertices P(0, 4), Q(4, 4), R(0, 0), and S(4, 0) are perpendicular bisectors of each other
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Answer:

The slope of diagonal PS is -1.

The slope of diagonal QR is 1.

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The midpoint of QR is (2, 2).

Perpendicular and share the same midpoint.

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2.6779*10^5

Step-by-step explanation:

The problem given is 2.69*10^5 - 1.21*10^3 which is 269000-1210=267790 -> 2.6779*10^5

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A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
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Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

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This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
1 year ago
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