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ipn [44]
2 years ago
5

The Carson family paid $192 for two adult and three youth tickets to an amusement park. At the same park, the Davis family paid

$148 for one adult and four youth tickets. Let x represent the cost of an adult ticket, and let y represent the cost of a youth ticket. Which system of equations can be used to find ticket cost?
x+y=192
x+y=148

2x+3y=192
4x+y=148

5x+5y=192
5x+5y=148

2x+3y=192
x+4y=148
Mathematics
2 answers:
ikadub [295]2 years ago
5 0
That would be the 4th one.
Andrei [34K]2 years ago
3 0

Answer: 2x + 3y = 192

x + 4y =148

Step-by-step explanation:

The cost of an adult ticket is represented by x

The cost of a youth ticket is represented by y.

The Carson family paid $192 for two adult and three youth tickets to an amusement park. This will be;

2x + 3y = 192

At the same park, the Davis family paid $148 for one adult and four youth tickets. This will be:

x + 4y = 148

Together both will be:

2x + 3y = 192

x + 4y =148

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Answer: The width of the garden is 18 feet. The area of the garden is 432ft^2.

Step-by-step explanation:

84-24*2=36

36/2=18

18*24= 432

8 0
2 years ago
A rectangular room has a width of 5 yards and length of 6 yards. How many square-feet carpet will be required for carpeting the
Sindrei [870]

Answer:

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Step-by-step explanation:

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W=5\ yd

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4 0
2 years ago
A researcher is using a repeated-measures design to test for mean differences among four treatment conditions. If the data for t
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Answer:

Step-by-step explanation:

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The data for this study consist of 10 scores in each treatment.

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6 0
2 years ago
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

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-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
2 years ago
Kate and Jean paint a house together in 6 days. If they work alone, Kate takes 5 fewer days than Jean would take to do the same
frutty [35]
Number of jobs=1

Time: 
<span>Since ‘x’ is given as a variable in the choices, we should reserve it for Kate and use ‘y’ for Jean as follows: </span>
<span>
Kate: => x </span>
<span>Jean: => y </span>

<span>But y = x - 5 </span>

<span>Combined rate: </span>
<span>1/x+ 1/y </span>
<span>= (x + y)/(xy) </span>

<span>Number of jobs done: </span>
<span>
Number of days X combined rate = number of jobs </span>
<span>6 [(x + y)/(xy)] = 1 </span>
<span>6x + 6y = xy </span>
<span>6x + 6(x - 5) = x(x - 5) </span>
<span>6x + 6x - 30 = x² - 5x </span>
<span>12x - 30 = x² - 5x </span>
<span>x² - 17x + 30 = 0 
</span>
Therefore, the answer would be A.
3 0
2 years ago
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