Answer:
Correct solution:
45.7 + 40.9 + 38.0 = 124.6 miles. 124.6 divided by 0.621 = 200.64
Step-by-step explanation:
they rode 45.7, 40.9, and 38 miles
= (45.7 + 40.9 + 38) miles
= 124.6 miles
Convert 124 .6 miles to kilometers
1 kilometer = 0.621 miles
124.60 miles = 124.60 / 0.621
= 200.64 kilometers
This is the correct solution because he divided 124.60 miles by 0.621
45.7 + 40.9 + 38.0 = 124.6 miles. 124.6 divided by 0.621 = 200.64
At the time the rocket hits the ground h=0, given that h=-16t²+320t+32
when h=0, our equation will be:
-16t²+320t+32=0
solving the above by completing square method we proceed as follows;
-16t²+320t+32=0
divide though by -16 we get
t²-20t-2=0
t²-20t=2
but
c=(-b/2a)^2
c=(20/2)^2
c=100
hence:
t²-20t+100=100+2
(t-10)(t-10)=102
√(t-10)²=√102
t-10=√102
hence
t=10+/-√102
t~20.1 or -0.1
since it must have taken long, then the answer is 20.1 sec
Answer:
25 more boxes is needed
Step-by-step explanation:
12000 batteries require 50 boxes. Let's find the unit rate.
That is, how many batteries are in each box??
That's 12,000/50!
12,000/50 = 240 batteries per box
Now, to find how many boxes we would need for 18,000 batteries, we will have to divide the total (18000) by 240(number of batteries per box). That is:
18,000/240 = 75 boxes
We would need 75 boxes to pack 18,000 batteries.
We want "how many MORE boxes needed", so we will the excess:
75 - 50 = 25 more boxes is needed
Answer:
a)0,45119
b)1
Step-by-step explanation:
For part A of the problem we must first find the probability that both people in the couple have the same birthday (April 30)
Now the poisson approximation is used
λ=nP=80000*1/133225=0,6
Now, let X be the number of couples that birth April 30
P(X ≥ 1) =
1 − P(X = 0) =
P(X ≥ 1) = 0,45119
B) Now want to find the
probability that both partners celebrated their birthday on th, assuming that the year is 52 weeks and therefore 52 thursday
Now the poisson approximation is used
λ=nP=80000*52/133225=31.225
Now, let X be the number of couples that birth same day
P(X ≥ 1) =
1 − P(X = 0) =
P(X ≥ 1) = 1
