Add 145, 156, 210. and 255 then divide by 4. The mean equals 184.
Answer:
0.64 seconds
Step-by-step explanation:
In the equation provided:
h = −16t2 + 4t + 4
h is the height of the ball and t is time. Since we want to find the time when the ball touches the floor, then height is 0. This leaves us with the equation
-16
+ 4t + 4 = 0
This is a quadratic equation can be solved with the following formula:

where a=-16
b=4
c=4
Solving for t we will find two different results:


Since time can't be negative, we discard t2 and choose t1.
Since it is required to answer in the nearest hundredth, we round the result to t=0.64 seconds.
Answer:
the probability that the project will be completed in 95 days or less, P(x ≤ 95) = 0.023
Step-by-step explanation:
This is a normal probability distribution question.
We'll need to standardize the 95 days to solve this.
The standardized score is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ
x = 95 days
xbar = mean = 105 days
σ = standard deviation = √(variance) = √25 = 5
z = (95 - 105)/5 = - 2
To determine the probability that the project will be completed in 95 days or less, P(x ≤ 95) = P(z ≤ (-2))
We'll use data from the normal probability table for these probabilities
P(x ≤ 95) = P(z ≤ (-2)) = 0.02275 = 0.023
Answer:
1.734
Step-by-step explanation:
Given that:
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).
The fitted regression is Time = −7.126 + .0214 Distance
Based on a sample size n = 20
And an Estimated standard error of the slope = 0.0053
the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:
Let's determine the degree of freedom df = n - 1
the degree of freedom df = 20 - 2
the degree of freedom df = 18
At the level of significance ∝ = 0.05 and degree of freedom df = 18
For a right tailed test t, the critical value from the t table is :
1.734