Which of the following is a binomial experiment? Rolling a six-sided number cube 24 times and recording if a 4 comes up Rolling
2 answers:
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Answer:
Step-by-step explanation:
1 ) Given that
For a non homogeneous part , we assume the particular solution is
2 ) Given that
For a non homogeneous part , we assume the particular solution is
3 ) Given that
y′′ + 4y′ + 20y = −3sin(2x)
For a non homogeneous part −3sin(2x) , we assume the particular solution is
4 ) Given that
y′′ − 2y′ − 15y = 3xcos(2x)
For a non homogeneous part 3xcos(2x) , we assume the particular solution is
Answer:
<h3>Pudge has 12 morethan apples that is 24 apples and both Ace and Christi has not more than 12 apples together they has atmost 12 apples.The apples does each having is</h3><h3>P = Pudge's Apples =24</h3><h3>A = Ace's Apples =8</h3><h3>and C = Christi's Apples=4.</h3>Step-by-step explanation:
Let P = Pudge's Apples
Let A = Ace's Apples
Let C = Christi's Apples
<h3>To find how many apples does each have if Pudge has 12 more than both Ace and Christi together:</h3>Given that P = 3A , A = 2C and P = A + C + 12
Substitute the value for P in P = A + C + 12 we get
3A = A + C + 12
3A-A=C+12
2A=C+12
From A = 2C we have that
Substitute the value C:
Substituting the value of A in P=3A we get
P = 3(8)
<h3>∴ P = 24 </h3>Substituting the values of P and A in P = A + C + 12
4=C
Rewritting we get
<h3>∴ C=4 </h3><h3>Hence Pudge has 12 morethan apples that is 24 apples </h3><h3>and both Ace and Christi has not more than 12 apples together they has atmost 12 apples</h3>