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SashulF [63]
1 year ago
5

A newly drilled water well produces 50,000 quarts of water per week. With no new water feeding the well, the production drops by

5% per year. Using 52 weeks in a year, what is the total number of quarts of water that can be drawn from this water well before it goes dry?
Mathematics
1 answer:
Sveta_85 [38]1 year ago
5 0

Answer:

Total amount of water = 5,200,000

Step-by-step explanation:

Given:

water produced = 50,000 quarts of water per week

Production drop = 5% = 0.05 per year

Number of week in year = 52 week

Find:

Total amount of water

Computation:

Sum = a / r

a = 50,000 x 52

a = 2,600,000

Sum = a / [1-r]

Sum = 2,600,000 / 5%

Sum = 2,600,000 / 0.05

Total amount of water = 5,200,000

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Jimmy’s Delicatessen sells large tins of Tom Tucker’s Toffee. The deli uses a periodic review system, checking inventory levels
Yakvenalex [24]

Answer:

The restocking level is 113 tins.

Step-by-step explanation:

Let the random variable <em>X</em> represents the restocking level.

The average demand during the reorder period and order lead time (13 days) is, <em>μ</em> = 91 tins.

The standard deviation of demand during this same 13- day period is, <em>σ</em> = 17 tins.

The service level that is desired is, 90%.

Compute the <em>z</em>-value for 90% desired service level as follows:

z_{\alpha}=z_{0.10}=1.282

*Use a <em>z</em>-table for the value.

The expression representing the restocking level is:

X=\mu +z \sigma

Compute the restocking level for a 90% desired service level as follows:

X=\mu +z \sigma

   =91+(1.282\times 17)\\=91+21.794\\=112.794\\\approx 113

Thus, the restocking level is 113 tins.

6 0
2 years ago
Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation,
xeze [42]

Answer:

D. x-\frac{5}{2}y =  \frac{25}{2}

Step-by-step explanation:

Given

y = \frac{2}{5}x - 5

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

x - \frac{5}{2}y = \frac{25}{2}

This is shown as follows;

y = \frac{2}{5}x - 5

Multiply both sides by \frac{5}{2}

\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)

Open Bracket

\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5

\frac{5}{2}y = x - \frac{25}{2}

Subtract x from both sides

\frac{5}{2}y - x = x -x - \frac{25}{2}

\frac{5}{2}y - x = - \frac{25}{2}

Multiply both sides by -1

-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1

-\frac{5}{2}y + x =  \frac{25}{2}

Reorder

x-\frac{5}{2}y =  \frac{25}{2}

<em>Hence, the correct option is D</em>

x-\frac{5}{2}y =  \frac{25}{2}

9 0
1 year ago
Read 2 more answers
(a) For what values of k does the function y = cos(kt) satisfy the differential equation 81y'' = −4y? (Enter your answers as a c
In-s [12.5K]

Answer:

k = \frac{2}{9}, k=\frac{-2}{9}

Step-by-step explanation:

The first case is a special case of the second one, so we will solve the question for the second case first.

Consider y = A\sin(kt) + B\cos(kt). Using the properties of derivatives and the derivatives of trigonometric functions we get that

y' = A\cdot k \cos(kt)- B \cdot k \sin(kt) = k (A\cos(kt)-B\sin(kt))

y'' = k(-A\cdot k \sin(kt)-B\cdot k \cos(kt)) = -k^2(y)

We have the equation 81y''=-4y. Note that since y'' = -k^2ythen we have the equation

-k^2 81y=-4y,

which implies that k^2 = \frac{4}{81}. Then, k=\pm\frac{2}{9}

Note that in this case, the value of k doesn't depend on the values of A and B. So, it applies to every value of A and B. The first case is included, since it is the case in which A=0 and B=1.

5 0
2 years ago
Find the answer The weight of an elephant is 10 to the 3rd power times the weight of a cat .If the the elephant weighs 14,000 po
Hitman42 [59]

Answer:

14\ pounds

Below is the procedure that was used to find the answer.

Step-by-step explanation:

Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.

According to the information provided in the exercise, we know that The weight of an elephant is 10^3 times the weight of a cat. Based on this we can write the following equation:

e=10^3c

If the weight in pounds of the elephant is:

e=14,000

We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.

Then we get:

14,000=10^3c\\\\\frac{14,000}{10^3}=c\\\\c=14

3 0
2 years ago
Which events are independent? Check all that apply. Each number 1 through 10 is written on a slip of paper, placed in a hat, and
asambeis [7]
Events that are independent:
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Please select this answer as the brainliest!
7 0
2 years ago
Read 3 more answers
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