Dividing Fractions Assignment Active Dividing Fractions with Fraction Bars Drag the divisN fraction to the dividend bar to see h
1 answer:
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<h3>Answer with explanation:</h3>
It is given that:
Circle 1 has center (−4, −7) and a radius of 12 cm.
Circle 2 has center (3, 4) and a radius of 15 cm.
Two circles are said to be similar if by some translation and dilation it could be placed over the other to form the same circle.
The circles are similar because the transformation rule ( x,y ) → (x+7,y+11) can be applied to Circle 1 and then dilate it using a scale factor of 5/4
( Since, as the center of circle 1 is (-4,-7)
so,
(-4+7,-7+11) → (3,4)
( Since, the radius of circle 1 is 12 and that of circle 2 is 15 cm.
so, let the scale factor be k .
that means :
)
Answer:
Measures are SV=9 units., SY=14 units, YW= , YW=
Step-by-step explanation:
Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.
As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.
Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.
Given ST=18 units.
As VY is perpendicular bisector implies SV=9 units.
Also in triangle VTY
⇒
⇒ VY^{2}=115
As vertices of triangle are equidistant from the circumcenter
⇒ SY=YT=UY=14 units
Hence, SY is 14 units
In ΔUWY,
⇒
⇒ ⇒ YW=
In ΔYXU,
⇒
⇒ ⇒ YW=
Hence, measures are SV=9 units., SY=14 units, YW= , YW=