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garik1379 [7]
2 years ago
13

Dividing Fractions Assignment Active Dividing Fractions with Fraction Bars Drag the divisN fraction to the dividend bar to see h

ow many parts of the diy sr are in the dividend. Use fraction bars and the rules of dividing signed numbers to divide 15 /15 5/ 3 Dividend 5 5 18 ow -9 Divisor OH-5 Intro Done​
Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
4 0

Answer:4

Step-by-step explanation:4

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Allen is showing his work in simplifying –8.3 + 9.2 – 4.4 + 3.7. Identify and explain any errors in his work or in his reasoning
avanturin [10]
Simplifying –8.3 + 9.2 – 4.4 + 3.7.

Identify and explain any errors in his work or in his reasoning

Original problem 1. −8.3 + 9.2 + 4.4 + 3.7

Additive inverse 2. −8.3 + 4.4 + 9.2 + 3.7 (error, not additive inverse; +3-3=0)

Commutative property 3. −8.3 + (4.4 + 9.2 + 3.7)

Associative property 4. −8.3 + 17.3

Simplify 5. 9
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2 years ago
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An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)
erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0
2 years ago
Suppose that a Coke/Pepsi survey was conducted of 400 randomly selected individuals from Gainesville. Two hundred people selecte
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Answer:

A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.

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2 years ago
OLYMPICS The number of men and women participating in the Winter
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Answer:I can’t see the rest.

Step-by-step explanation:

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2 years ago
Webassign find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (6, 36), an
Dvinal [7]
First find the tangent line

dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36

alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2

so we do \int\limits^6_0 {x^2} \, dx - \int\limits^6_0 {12x-36} \, dx = \int\limits^6_0 {x^2-(12x-36)} \, dx = \int\limits^6_0 {x^2-12x+36} \, dx =
[\frac{x^3}{3}-6x^2+36x]\limits^6_0=(\frac{6^3}{3}-6(6)^2+36(6))-(0)=\frac{216}{3}-216+216= 72+0=72

the area under the curve bounded by the lines and the x axis is 72 square units
4 0
2 years ago
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