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2 years ago

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What is the solution to the equation StartFraction 1 Over h minus 5 EndFraction + StartFraction 2 Over h + 5 EndFraction = Start

Fraction 16 Over h squared minus 25 EndFraction?
h = eleven-thirds
h = 5
h = 7
h = twenty-one-halves

2 answers:

vlabodo [156]2 years ago

7 0

Answer:

h=7

Step-by-step explanation:

djyliett [7]2 years ago

4 0

Answer:

h=7

Step-by-step explanation:

We want to solve the equation:

$\frac{1}{h-5}+\frac{2}{h+5}=\frac{16}{h^2-25}$

We multiply through by the LCM: $h^2-25=(h+5)(h-5)$

$(h^2-25*\frac{1}{h-5}+(h^2-25)*\frac{2}{h+5}=\frac{16}{h^2-25} \times(h^2-25)$

Simplify to get:

$h+5+2(h-5)=16$

We expand to get:

$h+5+2h-10=16$

$h+2h=16+10-5$ $3h=21$

h=7

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Identify the triangle that contains an acute angle for which the sine and cosine ratios are equal. 1. Triangle A B C has angle m

MAXImum [283]

Answer:

The correct option: (2) Triangle ABC that has angle measures 45°, 45° and 90°.

Step-by-step explanation:

It is provided that a triangle ABC has an acute angle for which the sine and cosine ratios are equal to 1.

Let the acute angle be m∠A.

For the sine and cosine ratio of m∠A to be equal to 1, the value of Sine of m∠A should be same as value of Cosine of m∠A.

The above predicament is possible for only one acute angle, i.e. 45°, since the value of Sin 45° and Cos 45° is,

$Sin\ 45^{o} =Cos\ 45^{o} = \frac{1}{\sqrt{2} }$

So for acute angle 45° the ratio of Sin 45° and Cos 45° is:

$\frac{Sin\ 45^{o}}{Cos\ 45^{o}} = \frac{\frac{1}{\sqrt{2} } }{\frac{1}{\sqrt{2} } } = 1$

Hence one of the angles of a triangle is, m∠A = 45°.

Comparing with the options provided the triangle is,

Triangle ABC that has angle measures 45°, 45° and 90°.

Thus, the provided triangle is a right angled isosceles triangle, since it has two similar angles.

7 0

2 years ago

A rectangular piece of land is 40m long and 25m wide. A path of uniform width and 426 m^2 area sorrounds

fredd [130]

Answer:

Width of the uniform path that surrounds the piece of land = 3 m

Step-by-step explanation:

Let the width of the path that surrounds the piece of land be x.

The situation described is sketched in the attached image to this solution.

The dimension of the Length of the piece of land including the uniform path that surrounds it = (40 + 2x) m

The Breadth of the piece of land including the uniform path that surrounds it = (25 + 2x) m

The area of the piece of land including the uniform path that surrounds it

= (Area of the piece of land) + (Area of the uniform path that surrounds it)

Area of the piece of land = Length × Breadth = 40 × 25 = 1000 m²

Area of the uniform path that surrounds it = 426 m² (Given in the question)

The area of the piece of land including the uniform path that surrounds it = 1000 + 426 = 1426 m²

But the area of the piece of land including the uniform path that surrounds it is also

= (Length of the piece of land including the uniform path that surrounds it) × (Breadth of the piece of land including the uniform path that surrounds it

= (40 + 2x) + (25 + 2x)

= 1000 + 80x + 50x + 4x²

= (4x² + 130x + 1000) m²

Equation these 2 areas

4x² + 130x + 1000 = 1426

4x² + 130x - 426 = 0

Solving the quadratic equation

x = 3 or -35.5

Since the width cannot be negative,

x = 3 m

Hope this Helps!!!

7 0

2 years ago

Which action will solve the equation?. m + 20 = 9. . Add 9 to each side.. Subtract 9 from each side.. Add 20 to each side.. Subt

Kruka [31]

M + 20 = 9
u need to subtract 20 from both sides because u want to isolate m

m + 20 = 9
m + 20 - 20 = 9 - 20
m = - 11

4 0

2 years ago

Read 2 more answers

3 Ximena draws an X shape in the coordinate plane as shown. Draw the images of

VARVARA [1.3K]

When a shape is rotated, it must be rotated around a point.

<em>See attachment for the image of each rotation.</em>

To do this, the top coordinates of the X shape will be transformed using the appropriate rotation rule; the same rule will then be applied to the other parts of the X shape.

The top coordinates of the X shape are:

$A = (0,0)$

$B = (1,0)$

$C = (3,0)$

$D =(4,0)$

For 90 degrees counterclockwise rotation, the rule is:

$(x,y) \to (-y,x)$

So, we have:

$A' = (0,0)$

$B' = (0,1)$

$C' = (0,3)$

$D' = (0,4)$

For 180 degrees rotation, the rule is:

$(x,y) \to (-x,-y)$

So, we have:

$A' = (0,0)$

$B' = (-1,0)$

$C' = (-3,0)$

$D' = (-4,0)$

For 270 degrees counter rotation, the rule is:

$(x,y) \to (y,-x)$

So, we have:

$A' = (0,0)$

$B' = (0,-1)$

$C' = (0,-3)$

$D' = (0,-4)$

See attachment for the image of each rotation

Read more about rotations at:

brainly.com/question/1571997

3 0

2 years ago

In order to estimate the average electricity usage per month, a sample of 125 residential customers were selected, and the month

mr_godi [17]

Answer:

[895.05; 940.81]kWh

Step-by-step explanation:

Hello!

Be X: monthly electricity usage by a residential customer

X~N

σ²: 12100KWh²

To estimate the population mean using a 98% CI you have to use the following formula

[X[bar]± $Z_{1-\alpha /2}$ * $\frac{Sigma}{\sqrt{n} }$ ]

1-α: 0.98

α0.02

α/2: 0.01

1-α/2:0.99

$Z_{1-\alpha /2}= Z_{0.99}= 2.326$

n= 125

X[bar]= ∑X/n= 228565/125= 917.93

[917.93±2.326 * $\frac{110}{\sqrt{125} }$ ]

[895.05; 940.81]

Using a 98% confidence level you'd expect that the interval [895.05; 940.81]kWh will include the average monthly electricity usage of residential customers.

I hope this helps!

Raw data:

Electric Usage

765

1139

714

687

1027

1109

749

799

911

631

975

717

1232

806

637

894

856

896

1272

1224

621

606

898

723

817

746

933

595

851

1027

770

685

750

1198

975

678

1050

886

826

1176

583

841

1188

692

733

791

584

1163

593

1234

603

1044

1233

1178

598

904

778

693

590

845

893

1028

975

788

1240

1253

854

1185

1164

741

1058

1053

795

1198

1240

1140

959

938

1008

1035

1085

1100

680

1006

977

1042

1252

943

1165

1014

912

791

612

935

864

953

667

1005

1063

1095

1086

810

1032

970

1099

1229

892

1074

579

754

1007

1116

583

763

1231

966

962

1132

738

1033

697

891

840

725

1031

7 0

2 years ago