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densk [106]
2 years ago
8

What is the solution to the equation StartFraction 1 Over h minus 5 EndFraction + StartFraction 2 Over h + 5 EndFraction = Start

Fraction 16 Over h squared minus 25 EndFraction?
h = eleven-thirds
h = 5
h = 7
h = twenty-one-halves
Mathematics
2 answers:
vlabodo [156]2 years ago
7 0

Answer:

h=7

Step-by-step explanation:

djyliett [7]2 years ago
4 0

Answer:

h=7

Step-by-step explanation:

We want to solve the equation:

\frac{1}{h-5}+\frac{2}{h+5}=\frac{16}{h^2-25}

We multiply through by the LCM: h^2-25=(h+5)(h-5)

(h^2-25*\frac{1}{h-5}+(h^2-25)*\frac{2}{h+5}=\frac{16}{h^2-25}   \times(h^2-25)

Simplify to get:

h+5+2(h-5)=16

We expand to get:

h+5+2h-10=16

h+2h=16+10-53h=21

h=7

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The state of south dakota has a population of about 814,000 people. Find the population density in people per square miles if th
Gnom [1K]

Remark

Not many per square mile. Sounds like an ideal place to live.

Step One

Find the number of Square Miles.

Area = Height * Width

Area = 380 * 200

Area = 76,000 square miles.

Step Two

Find the Density

<u>Formula</u>

Density = Population / Square Miles

Population = 814,000 people

Square miles = 76000

Solve

Density = 814000/76000 = 10.7 people per square mile.

Remark

Isn't that incredible. It means if all the Area of South Dakota were given to the people living there, each family of 4 would get roughly 1/2 a square mile.

4 0
2 years ago
Jackie runs and dances for 75 minutes every day.
Mumz [18]

Answer: A. x + y = 75 B. She spends 25 minutes running and 50 minutes dancing every day. C. Yes it is.

Step-by-step explanation: B. She spends 25 minutes running and 50 minutes dancing every day, because if she dances for 25 more minutes then she runs then we can minus 25 from 75 which we get 50. Then we take the 50 a divide it by 2 because of the two categories dancing and running. So we know she spends 25 minutes running then 25 minutes dancing but we need to add the 25 minutes to dancing. So she spends 25 minutes running and 50 dancing. C. Yes it is because she already dances for 50 minutes a day so all she needs to do is workout for 10 minutes less so 65 minutes one day.

6 0
2 years ago
Read 2 more answers
Which expression shows a way to find 20% of 950?<br> 950<br> 20<br> 20<br> What is it
Komok [63]
To find 20% of 950 you would set it up as a proportion. When doing percentages the prevent is always out of 100 so the first step would be 20/100. You are trying to find a number out of 950 so the second part would be ?/950. Now you want to cross multiply and divide. 20*950=19,000 then you divide it by 100 (your other number) 19,000/100=190. So 20% of 950 is 190.
3 0
1 year ago
Kelvin's monthly allowance is $42 and Mike's monthly allowance is $63. How many times Mike's monthly allowance is Kelvin's month
earnstyle [38]
It is 1.5 times because $63 divided by $42 is $1.5.
I hope this is what you meant. 
3 0
2 years ago
The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c
boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!} for x = 0, 1, 2, ...

where \lambda, the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is 1.2 \cdot 3 =3.6

The probability of exactly three flaws in 150 m of cable is

P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is 1.2 \cdot 2 =2.4

P(X\geq 2)=1-P(X

P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

(0.36143)(0.36143) = 0.13063

4 0
2 years ago
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