The battery life for Bruhier's cell phone is longer when he has fewer apps running. When only one app is running, the battery wi
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Answer:
Belinda's score is 32 strokes.
Step-by-step explanation:
Let the score of John be "x" and Belinda be "y".
It is given that, in the game of golf, John's score was 10 less than two times Belinda's score.
Also, John's score is 54 strokes.
The above equation can be written as ;
Here, x = 54,
Thus, Belinda's score is 32 strokes.
Answer:
(a) Probability mass function
P(X=0) = 0.0602
P(X=1) = 0.0908
P(X=2) = 0.1704
P(X=3) = 0.2055
P(X=4) = 0.1285
P(X=5) = 0.1550
P(X=6) = 0.1427
P(X=7) = 0.0390
P(X=8) = 0.0147
NOTE: the sum of the probabilities gives 1.0068 for rounding errors. It can be divided by 1.0068 to get the adjusted values.
(b) Cumulative distribution function of X
F(X=0) = 0.0602
F(X=1) = 0.1510
F(X=2) = 0.3214
F(X=3) = 0.5269
F(X=4) = 0.6554
F(X=5) = 0.8104
F(X=6) = 0.9531
F(X=7) = 0.9921
F(X=8) = 1.0068
Step-by-step explanation:
Let X be the number of people who arrive late to the seminar, we can assess that X can take values from 0 (everybody on time) to 8 (everybody late).
<u>For X=0</u>
This happens when every couple and the singles are on time (ot).
<u>For X=1</u>
This happens when only one single arrives late. It can be #4 or #5. As the probabilities are the same (P(#4=late)=P(#5=late)), we can multiply by 2 the former probability:
<u>For X=2</u>
This happens when
1) Only one of the three couples is late, and the others cooples and singles are on time.
2) When both singles are late , and the couples are on time.
<u>For X=3</u>
This happens when
1) Only one couple (3 posibilities) and one single are late (2 posibilities). This means there are 3*2=6 combinations of this.
<u>For X=4</u>
This happens when
1) Only two couples are late. There are 3 combinations of these.
2) Only one couple and both singles are late. Only one combination of these situation.
<u>For X=5</u>
This happens when
1) Only two couples (3 combinations) and one single are late (2 combinations). There are 6 combinations.
<u>For X=6</u>
This happens when
1) Only the three couples are late (1 combination)
2) Only two couples (3 combinations) and one single (2 combinations) are late
<u>For X=7</u>
This happens when
1) Only one of the singles is on time (2 combinations)
<u>For X=8</u>
This happens when everybody is late
Answer:
The probability that the yellow M&M came from the 1994 bag is 0.07407 or 7.407%
Step-by-step explanation:
Given
Before 1995
(Br) Brown = 30%
(Y) Yellow = 20% =0.2
(R) Red = 20%
(G) Green =10% =0.1
(O) Orange = 10%
(T) Tan = 10%
After 1995
(Br) Brown = 13%
(Y) Yellow = 14% =0.14
(R) Red = 13%
(G) Green = 20% = 0.2
(O) Orange = 16%
(Bl) Blue = 24%
Since there are two bags, let A be the bag from 1994, and B be the bag from 1996
Then let AY imply we drew a yellow M&M from the 1994 bag
AG implies we drew a green M&M from the 1994 bag
BY implies imply we drew a yellow M&M from the 1996 bag
BG implies we drew a green M&M from the 1996 bag
P(AY) =0.2
P (BY) = 0.14
P(AG) =0.1
P(BG) =0.2
Since the draws from the 1994 and 1996 bag are independent,
therefore
The draws can happen in either of the 2 ways in (1) and (2) above
therefore total probability E is given as
E =
For the yellow one to be from 1994, it implies that the event to be chosen is
Since the total probability is given as E=0.054
then
Concluding statement: This is the condition for the Yellow one to come from 1994 and green from 1996 provided that they obey the condition from E