Given that the<span> iq scores for large populations are centered at 100.
To get what percent of these 78 students have scores above 100 we conduct a normal distribution probability of the data.
P(x > 100) = P(z > (100 - 100)/sd) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 0.5 = 50%
</span>
Answer:
ft/min is the rate of changing of width
Step-by-step explanation:
Given -
The area always remain constant i.2 2 square feet.
Height of the rectangle = 2 feet
Rate of changing of height = 6 feet per minute
Since area is constant
2 sq ft = (2 * 6) ft/min * 1 * x ft/min
x =
ft/min
You will have infinite solutions
<h3>
Answer:</h3>
- f(x) = -2x^3 +3x^2 +11x -6
- see attached
- an infinite number. Since the magnitude of the leading coefficient is not specified, it may be any negative number. (We have chosen the smallest magnitude integer that makes all coefficients be integers.)
<h3>
Step-by-step explanation:</h3>
1. When "a" is a root of a polynomial, (x -a) is a factor of it. For the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).
In order to make the leading coefficient be negative, we need to multiply this product by a negative number. Any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.
Then ...
... f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)
... = -(2x² +3x -2)(x -3)
... = -(2x³ -3x² -11x +6)
... f(x) = -2x³ +3x² +11x -6
2. A graph created by the Desmos on-line graphing calculator is shown, and the zeros are highlighted.
3. As indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. You want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.
Answer:
Therefore the only statement that is not true is b.)
Step-by-step explanation:
There employees are 6 secretaries, 5 consultants and 4 partners in the firm.
a.) The probability that a secretary wins in the first draw
= 
b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.
p(secretary wins on second draw | consultant wins on first draw)
=
=
.
The probability that a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw =
is not true.
The probability that a secretary wins on the second draw = 
c.) The probability that a consultant wins on the first draw =

d.) The probability of two secretaries winning both tickets
= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)
= 
Therefore the only statement that is not true is b.)