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2 years ago

12

Jean can swim 100 meters in 1.86 minutes. Sean can swim the same distance in 2.12 minutes. Sean takes _____ of a minute longer t

han Jean to swim 100 meters.

2 answers:

sashaice [31]2 years ago

6 0

Answer:

Sean takes 0.26 of a minute longer than Jean to swim 100 meters.

Step-by-step explanation:

Given,

Time taken by Jean to swim 100 meters = 1.86 minutes,

While, the time taken by Sean to swim the same distance = 2.12 minutes,

Thus, the difference between the time taken by Sean and Jean = 2.12 minutes - 1.86 minutes

= 0.26 minutes,

Hence, Sean takes 0.26 of a minute longer than Jean to swim 100 meters.

attashe74 [19]2 years ago

4 0

.26 of a second, subtract 2.12 and 1.86 and you get .26

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Determine the t critical value(s) that will capture the desired t-curve area in each of the following cases. (Assume that centra

Triss [41]

Answer:

Step-by-step explanation:

a) this involves 2 tails

The critical value is determined from the t distribution table.

α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Looking at 0.975 with df 10

The critical value is 2.228

b) α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Looking at 0.975 with df 20

The critical value is 2.086

c) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Looking at 0.995 with df 20

The critical value is 2.845

d) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Looking at 0.995 with df 60

The critical value is 2.660

e) 1 - α = 1 - 0.01 = 0.99

Looking at 0.99 with df 10

The critical value is 2.764

f) 1 - α = 1 - 0.025 = 0.975

Looking at 0.975 with df 5

The critical value is 2.571

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2 years ago

Given: The coordinates of triangle PQR are P(0, 0), Q(2a, 0), and R(2b, 2c).

masha68 [24]

Answer:

The line containing the midpoints of two sides of a triangle is parallel to the third side ⇒ proved down

Step-by-step explanation:

* Lets revise the rules of the midpoint and the slope to prove the

problem

- The slope of a line whose endpoints are (x1 , y1) and (x2 , y2) is

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The mid-point of a line whose endpoints are (x1 , y1) and (x2 , y2) is

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

* Lets solve the problem

- PQR is a triangle of vertices P (0 , 0) , Q (2a , 0) , R (2b , 2c)

- Lets find the mid-poits of PQ called A

∵ Point P is (x1 , y1) and point Q is (x2 , y2)

∴ x1 = 0 , x2 = 2a and y1 = 0 , y2 = 0

∵ A is the mid-point of PQ

∴ $A=(\frac{0+2a}{2},\frac{0+0}{2})=(\frac{2a}{2},\frac{0}{2})=(a,0)$

- Lets find the mid-poits of PR which called B

∵ Point P is (x1 , y1) and point R is (x2 , y2)

∴ x1 = 0 , x2 = 2b and y1 = 0 , y2 = 2c

∵ B is the mid-point of PR

∴ $B=(\frac{0+2b}{2},\frac{0+2c}{2})=(\frac{2b}{2},\frac{2c}{2})=(b,c)$

- The parallel line have equal slopes, so lets find the slopes of AB and

QR to prove that they have same slopes then they are parallel

# Slope of AB

∵ Point A is (x1 , y1) and point B is (x2 , y2)

∵ Point A = (a , 0) and point B = (b , c)

∴ x1 = a , x2 = b and y1 = 0 and y2 = c

∴ The slope of AB is $m=\frac{c-0}{b-a}=\frac{c}{b-a}$

# Slope of QR

∵ Point Q is (x1 , y1) and point R is (x2 , y2)

∵ Point Q = (2a , 0) and point R = (2b , 2c)

∴ x1 = 2a , x2 = 2b and y1 = 0 and y2 = 2c

∴ The slope of AB is $m=\frac{2c-0}{2b-2a}=\frac{2c}{2(b-c)}=\frac{c}{b-a}$

∵ The slopes of AB and QR are equal

∴ AB // QR

∵ AB is the line containing the midpoints of PQ and PR of Δ PQR

∵ QR is the third side of the triangle

∴ The line containing the midpoints of two sides of a triangle is parallel

to the third side

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2 years ago

A committee of 15 members is voting on a proposal. Each member casts a yea or nay vote. On a random voting basis, what is the pr

Igoryamba

Answer:

0.006% probability that the final vote count is unanimous.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they vote yes, or they vote no. The probability of a person voting yes or no is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Random voting:

So 50% of voting yes, 50% no, so $p = 0.5$

15 members:

This means that $n = 15$

What is the probability that the final vote count is unanimous?

Either all vote no(P(X = 0)) or all vote yes(P(X = 15)). So

$p = P(X = 0) + P(X = 15)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.5)^{0}.(0.5)^{15} = 0.00003$

$P(X = 15) = C_{15,15}.(0.5)^{15}.(0.5)^{0} = 0.00003$

So

$p = P(X = 0) + P(X = 15) = 0.00003 + 0.00003 = 0.00006$

0.006% probability that the final vote count is unanimous.

7 0

1 year ago

Weekly demand for a particular item averages 30 units, with a standard deviation of 4. This item is managed with a fixed-order-i

aivan3 [116]

Answer:

(B)93

Explanation:

Since we are using a fixed-order-interval model,

The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand

$=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A$

Where:

d=weekly demand

OI=Order Interval

LT=Lead Time

z=Standard Deviation of Desired Service Level

$\sigma_{d}$ =Standard Deviation of weekly Demand

A= Amount at Hand

$=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A$

$[30(3 + 1)] + [1.964*4*\sqrt{3 + 1} - 43$

$= 120 + 15.712 - 43 = 92.7$

4 0

1 year ago

Jessica wants to buy a new chair that has a regular price of $75.00 this week the chair will be on sale at a 12% discount how mu

Novosadov [1.4K]

Answer: $9.

Step-by-step explanation:

It is given that,

Regular price of a new chair = $75.00

This week the chair will be on sale at a 12% discount. So,

Rate of discount = 12%

We need to find the amount of money that will Jessica save if she buys the chair this week.

$Discount=12\%\text{ of }\$75.00$

$Discount=75\times \dfrac{12}{100}$

$Discount=9$

Therefore, Jessica will save $9 if she buys the chair this week.

8 0

2 years ago