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lys-0071 [83]
2 years ago
8

An earth satellite remains in orbit at a distance of 11550 km from the center of the earth. what speed would it have to maintain

? the universal gravitational constant is 6.67 × 10−11 n · m2 /kg2 and the mass of the earth is 5.98 × 1024 kg. 1. 7093.03 2. 7236.86 3. 5374.04 4. 4845.11 5. 5292.47 6. 5876.55 7. 6477.61 8. 7600.32 9. 6223.84 10. 7414.21 answer in units of m/s.
Mathematics
1 answer:
marishachu [46]2 years ago
4 0
<span>11,550 km has to be changed to 11,550,000 meters

G · m · t² = 4 · π² · r³  we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span> <span> <span> <span> 6.083*10^22 </span> </span> </span> <span><span> </span> </span> / <span> <span> <span> 3.9</span></span></span>9 * 10^14
t^2 =  <span> <span> <span> 152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers

Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which  <em>is 5,670 meters per second.</em>


Source:
http://www.1728.org/kepler3a.htm



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