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shtirl [24]
2 years ago
10

Samantha and Mia each left Julia’s house at the same time. Mia walked north at 7 kilometers per hour. Samantha ran west at 11 ki

lometers per hour. How far apart were they after one hour? Round the answer to the nearest tenth.

Mathematics
2 answers:
lapo4ka [179]2 years ago
7 0

Answer: 13km

Step-by-step explanation:

Just took the test

Lena [83]2 years ago
3 0
Mia walked 7km/h so after 1 hour, she is 7 km north of the house of Julia

Samantha walked 11km/h so after 1 hour, she is 11 km west of the house of Julia.

The points where Mia and Samantha are after 1 hour , and the house of Julia form a right triangle with sides 7 and 11 km. The distance between the girls, is the hypotenuse of his triangle.

 by the pythagorean theorem:

MS= \sqrt{ 7^{2} + 11^{2} }= \sqrt{49+121}= \sqrt{170}=  13 (km)


Answer: 13 km

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You have just spoken to your insurance agent and you are interested in investing in a 20-Payment Life insurance policy. Given th
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Answer: You can use this to help you out:

Determine the term life insurance amount per thousand on a 20-year-old male for a 10-year policy given that the face value of the policy is $65,000 and the annual premium is $291.85.

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c.

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b.

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65,000÷1,000=65

So the term life insurance amount per thousand is

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Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

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So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

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2 years ago
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Solution:

The square of the given equation can be completed as below:

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